Monotonicity of Functions

Definition

Monotonicity of a Function

Let f(x)f(x) be defined on an interval II:

  • Strictly increasing: for any x1,x2Ix_1, x_2 \in I, if x1<x2x_1 < x_2 then f(x1)<f(x2)f(x_1) < f(x_2)
  • Increasing: for any x1,x2Ix_1, x_2 \in I, if x1<x2x_1 < x_2 then f(x1)f(x2)f(x_1) \leq f(x_2)
  • Strictly decreasing: for any x1,x2Ix_1, x_2 \in I, if x1<x2x_1 < x_2 then f(x1)>f(x2)f(x_1) > f(x_2)
  • Decreasing: for any x1,x2Ix_1, x_2 \in I, if x1<x2x_1 < x_2 then f(x1)f(x2)f(x_1) \geq f(x_2)

Geometric Meaning

  • The graph of an increasing function rises from left to right
  • The graph of a decreasing function falls from left to right

Examples

  • f(x)=x2f(x) = x^2 is strictly increasing on [0,+)[0, +\infty)
  • f(x)=x2f(x) = x^2 is strictly decreasing on (,0](-\infty, 0]
  • f(x)=sinxf(x) = \sin x is strictly increasing on [π2,π2][-\frac{\pi}{2}, \frac{\pi}{2}]

How to Test Monotonicity

  1. Definition method: use the definition directly
  2. Derivative method: for differentiable functions, decide monotonicity from the sign of the derivative
    • If f(x)>0f'(x) > 0, then f(x)f(x) is strictly increasing
    • If f(x)<0f'(x) < 0, then f(x)f(x) is strictly decreasing
    • If f(x)0f'(x) \geq 0, then f(x)f(x) is increasing (non-decreasing)
    • If f(x)0f'(x) \leq 0, then f(x)f(x) is decreasing (non-increasing)
  3. Graphical method: read monotonicity from the graph

Exercises

Exercise 1

Determine the monotonicity of f(x)=x33x+1f(x) = x^3 - 3x + 1 on R\mathbb{R}.

Answer and Explanation(4 个标签)
monotonicityderivativefunction graphcubic function

Approach: Use the derivative to decide monotonicity.

Detailed steps:

  1. Differentiate: f(x)=3x23=3(x21)=3(x1)(x+1)f'(x) = 3x^2 - 3 = 3(x^2 - 1) = 3(x-1)(x+1)
  2. Analyze the sign of the derivative:
    • When x<1x < -1, f(x)>0f'(x) > 0, so ff is strictly increasing
    • When 1<x<1-1 < x < 1, f(x)<0f'(x) < 0, so ff is strictly decreasing
    • When x>1x > 1, f(x)>0f'(x) > 0, so ff is strictly increasing

Answer: The function is strictly increasing on (,1](-\infty, -1] and [1,+)[1, +\infty), and strictly decreasing on [1,1][-1, 1].

Exercise 2

Determine the monotonicity of f(x)=x2+1xf(x) = \frac{x^2 + 1}{x} on (0,+)(0, +\infty).

Answer and Explanation(4 个标签)
monotonicityderivativefunction graphrational function

Approach: Use the derivative to decide monotonicity.

Detailed steps:

  1. Differentiate: f(x)=2xx(x2+1)1x2=2x2x21x2=x21x2f'(x) = \frac{2x \cdot x - (x^2 + 1) \cdot 1}{x^2} = \frac{2x^2 - x^2 - 1}{x^2} = \frac{x^2 - 1}{x^2}
  2. Analyze the sign of the derivative:
    • When 0<x<10 < x < 1, f(x)<0f'(x) < 0, so ff is strictly decreasing
    • When x>1x > 1, f(x)>0f'(x) > 0, so ff is strictly increasing

Answer: The function is strictly decreasing on (0,1](0, 1] and strictly increasing on [1,+)[1, +\infty).


Summary

Symbols Used in This Article

SymbolTypeReading/ExplanationMeaning in This Article
f(x)f(x)Math symbolf of xA function of variable xx
x1,x2x_1, x_2Math symbolx one, x twoTwo points inside the interval
f(x)f'(x)Math symbolf prime of xThe first derivative of the function
IIMath symbolIAn interval
R\mathbb{R}Math symbolReal numbersThe set of all real numbers

English–Chinese Glossary

English termChinese termPhoneticExplanation
monotonicity单调性/ˌmɒnəʊtəˈnɪsɪti/How function values change as the input grows
monotonically increasing单调递增/ˌmɒnəʊˈtɒnɪkli ɪnˈkriːsɪŋ/Values grow as the input grows
strictly monotonically increasing严格单调递增/ˈstrɪktli ˌmɒnəʊˈtɒnɪkli ɪnˈkriːsɪŋ/Values strictly grow as the input grows
monotonically decreasing单调递减/ˌmɒnəʊˈtɒnɪkli dɪˈkriːsɪŋ/Values shrink as the input grows
strictly monotonically decreasing严格单调递减/ˈstrɪktli ˌmɒnəʊˈtɒnɪkli dɪˈkriːsɪŋ/Values strictly shrink as the input grows
derivative导数/dɪˈrɪvətɪv/Rate of change of a function
inverse function反函数/ɪnˈvɜːs ˈfʌŋkʃən/The inverse mapping of a function
one-to-one correspondence一一对应/wʌn tuː wʌn ˌkɒrɪˈspɒndəns/Each input has one output and each output one input