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Implicit Functions

Definition

Definition of Implicit Functions

A functional relationship determined by the equation F(x,y)=0F(x, y) = 0 is called an implicit function.

Characteristics

Implicit functions have the following characteristics:

  • Non-explicit: Cannot directly solve for an explicit expression of y in terms of x
  • Equation-determined: The functional relationship needs to be determined through the equation
  • Multi-valuedness: Multiple function values may correspond to the same independent variable value
  • Locality: Implicit functions are usually valid only in certain regions

Common Examples

Circle Equation

x2+y2=1x^2 + y^2 = 1 determines an implicit function, which can be solved as:

  • y=1x2y = \sqrt{1 - x^2} (upper semicircle)
  • y=1x2y = -\sqrt{1 - x^2} (lower semicircle)

Ellipse Equation

x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1 determines an implicit function

Other Examples

  • x3+y3=3xyx^3 + y^3 = 3xy (Folium of Descartes)
  • ex+ey=1e^x + e^y = 1
  • sin(x+y)=x+y\sin(x + y) = x + y

Implicit Function Differentiation Methods

Basic Steps

  1. Differentiate both sides of the equation with respect to x
  2. Use the chain rule to handle the derivative of y
  3. Solve for dydx\frac{dy}{dx}

Specific Method

For the equation F(x,y)=0F(x, y) = 0:

  1. Differentiate both sides with respect to x: Fx+Fydydx=0\frac{\partial F}{\partial x} + \frac{\partial F}{\partial y} \cdot \frac{dy}{dx} = 0

  2. Solve for dydx\frac{dy}{dx}: dydx=FxFy\frac{dy}{dx} = -\frac{\frac{\partial F}{\partial x}}{\frac{\partial F}{\partial y}}

Notes

  • Denominator not zero: Fy0\frac{\partial F}{\partial y} \neq 0
  • Locality: The result is valid only near certain points
  • Multi-valuedness: May need to consider multiple branches

Examples of Implicit Function Differentiation

Example 1: Derivative of Circle

For x2+y2=1x^2 + y^2 = 1:

  1. Differentiate both sides: 2x+2ydydx=02x + 2y \cdot \frac{dy}{dx} = 0
  2. Solve for the derivative: dydx=xy\frac{dy}{dx} = -\frac{x}{y}

Example 2: Derivative of Ellipse

For x2a2+y2b2=1\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1:

  1. Differentiate both sides: 2xa2+2yb2dydx=0\frac{2x}{a^2} + \frac{2y}{b^2} \cdot \frac{dy}{dx} = 0
  2. Solve for the derivative: dydx=b2xa2y\frac{dy}{dx} = -\frac{b^2 x}{a^2 y}

Exercises

Exercise 1

Find the derivative of the implicit function x2+y2=4x^2 + y^2 = 4 at the point (1,3)(1, \sqrt{3}).

Reference Answer (2 个标签)
implicit function differentiation

Solution Approach: Differentiate both sides of the equation with respect to x, then solve for dydx\frac{dy}{dx}.

Detailed Steps:

  1. Differentiate both sides of x2+y2=4x^2 + y^2 = 4 with respect to x: 2x+2ydydx=02x + 2y \cdot \frac{dy}{dx} = 0
  2. Solve for dydx\frac{dy}{dx}: 2ydydx=2x2y \cdot \frac{dy}{dx} = -2x dydx=xy\frac{dy}{dx} = -\frac{x}{y}
  3. Substitute the point (1,3)(1, \sqrt{3}): dydx=13=33\frac{dy}{dx} = -\frac{1}{\sqrt{3}} = -\frac{\sqrt{3}}{3}

Answer: The derivative at point (1,3)(1, \sqrt{3}) is 33-\frac{\sqrt{3}}{3}.

Exercise 2

Find the derivative of the implicit function x3+y3=3xyx^3 + y^3 = 3xy.

Reference Answer (2 个标签)
implicit function differentiation

Solution Approach: Differentiate both sides of the equation with respect to x, then solve for dydx\frac{dy}{dx}.

Detailed Steps:

  1. Differentiate both sides of x3+y3=3xyx^3 + y^3 = 3xy with respect to x: 3x2+3y2dydx=3y+3xdydx3x^2 + 3y^2 \cdot \frac{dy}{dx} = 3y + 3x \cdot \frac{dy}{dx}
  2. Rearrange the equation: 3y2dydx3xdydx=3y3x23y^2 \cdot \frac{dy}{dx} - 3x \cdot \frac{dy}{dx} = 3y - 3x^2 (3y23x)dydx=3y3x2(3y^2 - 3x) \cdot \frac{dy}{dx} = 3y - 3x^2
  3. Solve for dydx\frac{dy}{dx}: dydx=3y3x23y23x=yx2y2x\frac{dy}{dx} = \frac{3y - 3x^2}{3y^2 - 3x} = \frac{y - x^2}{y^2 - x}

Answer: dydx=yx2y2x\frac{dy}{dx} = \frac{y - x^2}{y^2 - x}.

Exercise 3

Find the derivative of the implicit function ex+ey=1e^x + e^y = 1.

Reference Answer (2 个标签)
implicit function differentiation

Solution Approach: Differentiate both sides of the equation with respect to x, then solve for dydx\frac{dy}{dx}.

Detailed Steps:

  1. Differentiate both sides of ex+ey=1e^x + e^y = 1 with respect to x: ex+eydydx=0e^x + e^y \cdot \frac{dy}{dx} = 0
  2. Solve for dydx\frac{dy}{dx}: eydydx=exe^y \cdot \frac{dy}{dx} = -e^x dydx=exey=exy\frac{dy}{dx} = -\frac{e^x}{e^y} = -e^{x-y}

Answer: dydx=exy\frac{dy}{dx} = -e^{x-y}.


Summary

Symbols Appearing in This Article

SymbolTypePronunciation/ExplanationMeaning in This Article
F(x,y)F(x, y)Mathematical SymbolF of x and yFunction of two variables
F(x,y)=0F(x, y) = 0Mathematical SymbolF of x and y equals zeroImplicit function equation
dydx\frac{dy}{dx}Mathematical Symboldy by dxDerivative of y with respect to x
Fx\frac{\partial F}{\partial x}Mathematical Symbolpartial F by partial xPartial derivative of FF with respect to xx
Fy\frac{\partial F}{\partial y}Mathematical Symbolpartial F by partial yPartial derivative of FF with respect to yy
exe^xMathematical Symbole to the power xExponential function with base ee
eye^yMathematical Symbole to the power yExponential function with base ee
sin(x+y)\sin(x + y)Mathematical Symbolsine of x plus ySine function

Chinese-English Glossary

Chinese TermEnglish TermPhoneticExplanation
隐函数implicit function/ɪmˈplɪsɪt ˈfʌŋkʃən/Functional relationship determined by an equation
显式函数explicit function/ɪkˈsplɪsɪt ˈfʌŋkʃən/Function that can be directly expressed as y in terms of x
隐函数求导implicit differentiation/ɪmˈplɪsɪt ˌdɪfəˌrenʃɪˈeɪʃən/Method for finding derivatives of implicit functions
偏导数partial derivative/ˈpɑːʃəl dɪˈrɪvətɪv/Derivative of a multivariable function with respect to one variable
链式法则chain rule/tʃeɪn ruːl/Rule for differentiating composite functions
多值性multi-valuedness/ˌmʌlti ˈvæljudnəs/Property where one independent variable corresponds to multiple function values
局部性locality/ləʊˈkælɪti/Property where function is valid only in certain regions
分支branch/brɑːntʃ/Different solutions of implicit functions
笛卡尔叶形线Folium of Descartes/ˈfəʊliəm əv deɪˈkɑːrt/Curve determined by the equation x3+y3=3xyx^3 + y^3 = 3xy

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