Continuity of Trigonometric Functions

Trigonometric functions are an important type of function in calculus; understanding their continuity properties is essential for studying more complicated types of function.

Basic Properties

Trigonometric functions have the following basic properties:

  • Periodicity: have periodic features
  • Continuity: sin⁡x\sin x and cos⁡x\cos x are continuous on R\mathbb{R}
  • Discontinuity: tan⁡x\tan x and cot⁡x\cot x are discontinuous at certain points
  • Graph features: a smooth curve, with no jumps or breaks

Continuous Trigonometric Functions

The Sine and Cosine Functions

Sine function: f(x)=sin⁡xf(x) = \sin x

Properties:

  • Domain: R\mathbb{R}
  • Continuous on R\mathbb{R}
  • Period 2π2\pi
  • Range: [−1,1][-1, 1]

Cosine function: f(x)=cos⁡xf(x) = \cos x

Properties:

  • Domain: R\mathbb{R}
  • Continuous on R\mathbb{R}
  • Period 2π2\pi
  • Range: [−1,1][-1, 1]

Proof of Continuity

Continuity of Trigonometric Functions

sin⁡x\sin x and cos⁡x\cos x are continuous everywhere on R\mathbb{R}.

Proof Strategy:

  1. Use the definitions of the trigonometric functions and the properties of limits
  2. Prove continuity at an arbitrary point x0x_0
  3. Use the periodicity of the trigonometric functions

Discontinuous Trigonometric Functions

The Tangent Function

Tangent Function

f(x)=tan⁡xf(x) = \tan x

Properties:

  • Domain: x≠π2+kπx \neq \frac{\pi}{2} + k\pi (kk an integer)
  • Continuous on its domain
  • Period π\pi
  • Range: R\mathbb{R}
  • Has a vertical asymptote at every point of discontinuity

Analysis of the points of discontinuity:

  • Points of discontinuity: x=π2+kπx = \frac{\pi}{2} + k\pi (kk an integer)
  • Left limit: lim⁡x→(π2+kπ)−tan⁡x=+∞\lim_{x \to (\frac{\pi}{2} + k\pi)^-} \tan x = +\infty
  • Right limit: lim⁡x→(π2+kπ)+tan⁡x=−∞\lim_{x \to (\frac{\pi}{2} + k\pi)^+} \tan x = -\infty
  • These are discontinuities of the second kind

The Cotangent Function

Cotangent Function

f(x)=cot⁡xf(x) = \cot x

Properties:

  • Domain: x≠kπx \neq k\pi (kk an integer)
  • Continuous on its domain
  • Period π\pi
  • Range: R\mathbb{R}
  • Has a vertical asymptote at every point of discontinuity

Analysis of the points of discontinuity:

  • Points of discontinuity: x=kπx = k\pi (kk an integer)
  • Left limit: lim⁡x→(kπ)−cot⁡x=−∞\lim_{x \to (k\pi)^-} \cot x = -\infty
  • Right limit: lim⁡x→(kπ)+cot⁡x=+∞\lim_{x \to (k\pi)^+} \cot x = +\infty
  • These are discontinuities of the second kind

The Secant and Cosecant Functions

Secant function: f(x)=sec⁡x=1cos⁡xf(x) = \sec x = \frac{1}{\cos x}

Properties:

  • Domain: x≠π2+kπx \neq \frac{\pi}{2} + k\pi (kk an integer)
  • Continuous on its domain
  • Period 2π2\pi
  • Has a vertical asymptote at every point of discontinuity

Cosecant function: f(x)=csc⁡x=1sin⁡xf(x) = \csc x = \frac{1}{\sin x}

Properties:

  • Domain: x≠kπx \neq k\pi (kk an integer)
  • Continuous on its domain
  • Period 2π2\pi
  • Has a vertical asymptote at every point of discontinuity

Continuity of Composite Trigonometric Functions

Basic Theorem

If the function f(x)f(x) is continuous at x0x_0, then sin⁡(f(x))\sin(f(x)) and cos⁡(f(x))\cos(f(x)) are continuous at x0x_0.

Examples

Example 1: f(x)=sin⁡(x2)f(x) = \sin(x^2)

Analysis:

  • The inner function g(x)=x2g(x) = x^2 is continuous on R\mathbb{R}
  • The outer function h(x)=sin⁡xh(x) = \sin x is continuous on R\mathbb{R}
  • Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous on R\mathbb{R}

Example 2: f(x)=cos⁡(ln⁡x)f(x) = \cos(\ln x)

Analysis:

  • The inner function g(x)=ln⁡xg(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  • The outer function h(x)=cos⁡xh(x) = \cos x is continuous on R\mathbb{R}
  • Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous on (0,+∞)(0, +\infty)

Example 3: f(x)=tan⁡(x2)f(x) = \tan(x^2)

Analysis:

  • The inner function g(x)=x2g(x) = x^2 is continuous on R\mathbb{R}
  • The outer function h(x)=tan⁡xh(x) = \tan x is continuous on its domain
  • Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous on its domain
  • Points of discontinuity: those where x2=π2+kπx^2 = \frac{\pi}{2} + k\pi, that is, x=±π2+kπx = \pm\sqrt{\frac{\pi}{2} + k\pi}

Graph Characteristics of Trigonometric Functions

Summary of Graph Features

  1. Periodicity: trigonometric functions are periodic, so the graph repeats itself
  2. Smoothness: on its domain, the graph of a trigonometric function is a smooth curve
  3. Asymptotes: there is a vertical asymptote at every point of discontinuity
  4. Symmetry: sin⁡x\sin x is an odd function and cos⁡x\cos x is an even function

Applications of Trigonometric Functions

1. Physical Modelling

Trigonometric functions are widely used in physics:

  • Vibration: describe simple harmonic motion
  • Wave motion: describe various wave phenomena
  • Periodic phenomena: describe periodic physical phenomena

2. Engineering Applications

Trigonometric functions have important applications in engineering:

  • Signal processing: Fourier analysis
  • Circuit analysis: analysis of alternating-current circuits
  • Mechanical design: kinematic analysis

Exercises

Exercise 1

Determine the continuity of f(x)=sin⁡xf(x) = \sin x on R\mathbb{R}.

trigonometric functioncontinuityfunction continuity

Approach: Use the basic results about the continuity of elementary functions.

Steps:

  1. sin⁡x\sin x is a basic elementary function (a trigonometric function)
  2. By the continuity theorem for elementary functions, every elementary function is continuous on its domain
  3. The domain of sin⁡x\sin x is R\mathbb{R}

Answer: sin⁡x\sin x is continuous everywhere on R\mathbb{R}.

Exercise 2

Determine the continuity of f(x)=tan⁡(x2)f(x) = \tan(x^2) at x=0x = 0.

trigonometric functioncontinuityfunction continuity

Approach: Use the continuity of composite functions.

Steps:

  1. The inner function g(x)=x2g(x) = x^2 is continuous on R\mathbb{R}
  2. The outer function h(x)=tan⁡xh(x) = \tan x is continuous on its domain
  3. Since x2≥0x^2 \geq 0, and tan⁡x\tan x is continuous at x=0x = 0
  4. Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous at x=0x = 0

Answer: The function is continuous at x=0x = 0.

Exercise 3

Determine the continuity of f(x)=cos⁡(ln⁡x)f(x) = \cos(\ln x) at x=1x = 1.

trigonometric functioncontinuityfunction continuity

Approach: Use the continuity of composite functions.

Steps:

  1. The inner function g(x)=ln⁡xg(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  2. The outer function h(x)=cos⁡xh(x) = \cos x is continuous on R\mathbb{R}
  3. Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous on (0,+∞)(0, +\infty)
  4. In particular, f(x)f(x) is continuous at x=1x = 1

Answer: The function is continuous at x=1x = 1.

Exercise 4

Determine the continuity of f(x)=tan⁡(sin⁡x)f(x) = \tan(\sin x) on R\mathbb{R}.

trigonometric functioncontinuityfunction continuity

Approach: Use the continuity of composite functions.

Steps:

  1. The inner function g(x)=sin⁡xg(x) = \sin x is continuous on R\mathbb{R}
  2. The outer function h(x)=tan⁡xh(x) = \tan x is continuous on its domain
  3. Since sin⁡x∈[−1,1]\sin x \in [-1, 1], and tan⁡x\tan x is continuous on [−1,1][-1, 1]
  4. Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous on R\mathbb{R}

Answer: The function is continuous on R\mathbb{R}.

Exercise 5

Determine the continuity of f(x)=sin⁡(1x)f(x) = \sin(\frac{1}{x}) at x=0x = 0.

trigonometric functioncontinuityfunction continuity

Approach: Check whether the function is defined at that point.

Steps:

  1. The function is undefined at x=0x = 0
  2. Therefore the function is discontinuous at x=0x = 0

Answer: The function is discontinuous at x=0x = 0, because the function is undefined at that point.

Exercise 6

Let f(x)={sin⁡x,x≤0x+1,x>0f(x) = \begin{cases} \sin x, & x \leq 0 \\ x + 1, & x > 0 \end{cases}. Determine the continuity of f(x)f(x) at x=0x = 0.

trigonometric functioncontinuityfunction continuity

Approach: Compute the left limit, the right limit and the function value separately, and check whether the three are equal.

Steps:

  1. Left limit: lim⁡x→0−f(x)=lim⁡x→0−sin⁡x=0\lim_{x \to 0^-} f(x) = \lim_{x \to 0^-} \sin x = 0
  2. Right limit: lim⁡x→0+f(x)=lim⁡x→0+(x+1)=1\lim_{x \to 0^+} f(x) = \lim_{x \to 0^+} (x + 1) = 1
  3. Function value: f(0)=sin⁡0=0f(0) = \sin 0 = 0
  4. The left limit and the right limit are not equal, so the function is discontinuous at x=0x = 0

Answer: The function is discontinuous at x=0x = 0; this is a jump discontinuity.


Summary

Symbols Used in This Article

SymbolTypePronunciation/ExplanationMeaning in This Article
R\mathbb{R}Mathematical symbolBlackboard bold R (Real numbers)The set of all real numbers
π\piGreek letterPi (pi)The ratio of a circle’s circumference to its diameter, used to denote angles (such as π2\frac{\pi}{2}, π\pi, 2π2\pi)

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