Logarithmic Function

The logarithmic function is an important type of function in calculus with distinctive properties. Understanding the continuity properties of logarithmic functions is essential for studying more complicated types of function.

Basic Properties

The logarithmic function has the following basic properties:

  • Monotonicity: the logarithmic function is a monotone function
  • Continuity: continuous on its domain
  • Differentiability: differentiable on its domain
  • Inverse relation: the logarithmic function and the exponential function are inverses of each other

The Natural Logarithmic Function

Definition of the Natural Logarithmic Function

f(x)=ln⁡xf(x) = \ln x

The natural logarithmic function is the logarithm with base ee.

Properties:

  • Domain: (0,+∞)(0, +\infty)
  • Continuous on its domain
  • The graph is a monotonically increasing logarithmic curve
  • Range: R\mathbb{R}
  • Derivative: f′(x)=1xf'(x) = \frac{1}{x}

The General Logarithmic Function

Definition of the General Logarithmic Function

f(x)=log⁡axf(x) = \log_a x (a>0,a≠1a > 0, a \neq 1)

where aa is the base.

Properties:

  • Domain: (0,+∞)(0, +\infty)
  • Continuous on its domain
  • Monotonically increasing when a>1a > 1, monotonically decreasing when 0<a<10 < a < 1
  • Range: R\mathbb{R}
  • Derivative: f′(x)=1xln⁡af'(x) = \frac{1}{x \ln a}

Graph Characteristics of Logarithmic Functions

  1. Monotonicity: the logarithmic function is monotone on its domain
  2. Asymptotes: there is a vertical asymptote x=0x = 0
  3. Smoothness: the graph is a smooth curve, with no corners or breaks
  4. Growth: the logarithmic function grows slowly

Continuity Analysis of Logarithmic Functions

Determining Continuity

The logarithmic function is continuous on (0,+∞)(0, +\infty).

Proof of Continuity

The continuity of the logarithmic function rests on the following facts:

  1. Continuity of inverse functions: the inverse of a continuous function is continuous
  2. Continuity of the exponential function: the exponential function exe^x is continuous on R\mathbb{R}
  3. The logarithmic function is the inverse of the exponential function: ln⁡x\ln x is the inverse of exe^x
  4. Hence the logarithmic function is continuous: ln⁡x\ln x is continuous on (0,+∞)(0, +\infty)

Continuity of Composite Functions

Basic Theorem

If the function f(x)f(x) is continuous at x0x_0 and f(x0)>0f(x_0) > 0, then ln⁡f(x)\ln f(x) is continuous at x0x_0.

Examples

Example 1: f(x)=ln⁡(x2+1)f(x) = \ln(x^2 + 1)

Analysis:

  • The inner function h(x)=x2+1h(x) = x^2 + 1 is continuous on R\mathbb{R}
  • The outer function g(x)=ln⁡xg(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  • Since x2+1>0x^2 + 1 > 0 holds for every x∈Rx \in \mathbb{R}
  • Therefore f(x)=g(h(x))f(x) = g(h(x)) is continuous on R\mathbb{R}

Example 2: f(x)=ln⁡(x2−1)f(x) = \ln(x^2 - 1)

Analysis:

  • The inner function h(x)=x2−1h(x) = x^2 - 1 is continuous on R\mathbb{R}
  • The outer function g(x)=ln⁡xg(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  • We need x2−1>0x^2 - 1 > 0, that is, x<−1x < -1 or x>1x > 1
  • Therefore f(x)f(x) is continuous on (−∞,−1)∪(1,+∞)(-\infty, -1) \cup (1, +\infty)

Example 3: f(x)=ln⁡(cos⁡x)f(x) = \ln(\cos x)

Analysis:

  • The inner function h(x)=cos⁡xh(x) = \cos x is continuous on R\mathbb{R}
  • The outer function g(x)=ln⁡xg(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  • We need cos⁡x>0\cos x > 0
  • Therefore f(x)f(x) is continuous at every value for which cos⁡x>0\cos x > 0 holds, that is, every xx value

The Relation Between Logarithmic and Exponential Functions

They Are Inverses of Each Other

The logarithmic function and the exponential function are inverses of each other:

  • ln⁡(ex)=x\ln(e^x) = x for every x∈Rx \in \mathbb{R}
  • eln⁡x=xe^{\ln x} = x for every x>0x > 0

Composite Functions

Example: f(x)=eln⁡xf(x) = e^{\ln x}

Analysis:

  • The inner function h(x)=ln⁡xh(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  • The outer function g(x)=exg(x) = e^x is continuous on R\mathbb{R}
  • Therefore f(x)=g(h(x))f(x) = g(h(x)) is continuous on (0,+∞)(0, +\infty)
  • In fact f(x)=xf(x) = x (when x>0x > 0)

Exercises

Exercise 1

Determine the continuity of f(x)=ln⁡(x2+1)f(x) = \ln(x^2 + 1) on R\mathbb{R}.

logarithmic functioncontinuityfunction continuity

Approach: Analyse the continuity of the composite function.

Steps:

  1. The inner function g(x)=x2+1g(x) = x^2 + 1 is continuous on R\mathbb{R}
  2. The outer function h(x)=ln⁡xh(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  3. Since x2+1>0x^2 + 1 > 0 holds for every x∈Rx \in \mathbb{R}
  4. Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous on R\mathbb{R}

Answer: The function is continuous on R\mathbb{R}.

Exercise 2

Determine the intervals of continuity of f(x)=ln⁡(x2−1)f(x) = \ln(x^2 - 1).

logarithmic functioncontinuityfunction continuity

Approach: Analyse the domain and the continuity of the composite function.

Steps:

  1. The inner function g(x)=x2−1g(x) = x^2 - 1 is continuous on R\mathbb{R}
  2. The outer function h(x)=ln⁡xh(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  3. We need x2−1>0x^2 - 1 > 0, that is, x<−1x < -1 or x>1x > 1
  4. Therefore the interval of continuity is (−∞,−1)∪(1,+∞)(-\infty, -1) \cup (1, +\infty)

Answer: The interval of continuity is (−∞,−1)∪(1,+∞)(-\infty, -1) \cup (1, +\infty).

Exercise 3

Determine the intervals of continuity of f(x)=ln⁡(cos⁡x)f(x) = \ln(\cos x).

logarithmic functioncontinuityfunction continuity

Approach: Analyse the domain and the continuity of the composite function.

Steps:

  1. The inner function g(x)=cos⁡xg(x) = \cos x is continuous on R\mathbb{R}
  2. The outer function h(x)=ln⁡xh(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  3. We need cos⁡x>0\cos x > 0
  4. Therefore the interval of continuity is all the values for which cos⁡x>0\cos x > 0 holds, i.e. all the xx values that satisfy it

Answer: The interval of continuity is all the values for which cos⁡x>0\cos x > 0 holds, i.e. all the xx values that satisfy it.

Exercise 4

Determine the continuity of f(x)=log⁡2xf(x) = \log_2 x on (0,+∞)(0, +\infty).

logarithmic functioncontinuityfunction continuity

Approach: The general logarithmic function is continuous on its domain.

Steps:

  1. f(x)=log⁡2xf(x) = \log_2 x is a general logarithmic function with base a=2>1a = 2 > 1
  2. The domain of the logarithmic function is (0,+∞)(0, +\infty)
  3. The logarithmic function is continuous everywhere on its domain
  4. Therefore f(x)f(x) is continuous on (0,+∞)(0, +\infty)

Answer: The function is continuous on (0,+∞)(0, +\infty).


Summary

Symbols Used in This Article

SymbolTypePronunciation/ExplanationMeaning in This Article
R\mathbb{R}Mathematical symbolBlackboard bold R (Real numbers)The set of all real numbers
ln⁡\lnMathematical symbolNatural logarithmThe logarithm with base ee
log⁡a\log_aMathematical symbolLogarithmThe logarithm with base aa

Found an issue with this content?

Tell us what could be improved.