Trigonometric Function

Trigonometric functions are an important type of function in calculus and have periodic features. Understanding the continuity properties of trigonometric functions is essential for studying more complicated types of function.

Basic Properties

A trigonometric function has the following basic properties:

  • Domain: R\mathbb{R} (for sin⁡x\sin x and cos⁡x\cos x)
  • Continuity: continuous everywhere on its domain
  • Periodicity: has periodic features
  • Boundedness: the function values are bounded

Common Trigonometric Functions

1. Sine Function

Sine Function

f(x)=sin⁡xf(x) = \sin x

Properties:

  • Domain: R\mathbb{R}
  • Continuous everywhere on R\mathbb{R}
  • Period 2π2\pi
  • Range: [−1,1][-1, 1]
  • The graph is a sine curve

2. Cosine Function

Cosine Function

f(x)=cos⁡xf(x) = \cos x

Properties:

  • Domain: R\mathbb{R}
  • Continuous everywhere on R\mathbb{R}
  • Period 2π2\pi
  • Range: [−1,1][-1, 1]
  • The graph is a cosine curve

3. Tangent Function

Tangent Function

f(x)=tan⁡xf(x) = \tan x

Properties:

  • Domain: x≠π2+kπx \neq \frac{\pi}{2} + k\pi (kk an integer)
  • Continuous on its domain
  • Period π\pi
  • Range: R\mathbb{R}
  • Has a vertical asymptote at every point of discontinuity

4. Cotangent Function

Cotangent Function

f(x)=cot⁡xf(x) = \cot x

Properties:

  • Domain: x≠kπx \neq k\pi (kk an integer)
  • Continuous on its domain
  • Period π\pi
  • Range: R\mathbb{R}
  • Has a vertical asymptote at every point of discontinuity

Continuity Analysis of Trigonometric Functions

Determining Continuity

  1. sin⁡x\sin x and cos⁡x\cos x: continuous everywhere on R\mathbb{R}
  2. tan⁡x\tan x and cot⁡x\cot x: continuous on their domains, with a vertical asymptote at every point of discontinuity

Proof of Continuity

The continuity of the trigonometric functions rests on the following facts:

  1. Power series expansion: sin⁡x\sin x and cos⁡x\cos x can be written as power series
  2. Continuity of power series: a power series is continuous within its interval of convergence
  3. Continuity of composite functions: the composite of continuous functions is continuous

Graph Characteristics of Trigonometric Functions

Summary of Graph Features

  1. Periodicity: trigonometric functions are periodic, so the graph repeats itself
  2. Smoothness: on its domain, the graph of a trigonometric function is a smooth curve
  3. Boundedness: sin⁡x\sin x and cos⁡x\cos x are bounded, while tan⁡x\tan x and cot⁡x\cot x are unbounded
  4. Symmetry: sin⁡x\sin x is an odd function and cos⁡x\cos x is an even function

Continuity of Composite Trigonometric Functions

Basic Theorem

If the function f(x)f(x) is continuous at x0x_0, then sin⁡(f(x))\sin(f(x)) and cos⁡(f(x))\cos(f(x)) are continuous at x0x_0.

Examples

Example 1: f(x)=sin⁡(x2+1)f(x) = \sin(x^2 + 1)

Analysis:

  • The inner function h(x)=x2+1h(x) = x^2 + 1 is continuous on R\mathbb{R}
  • The outer function g(x)=sin⁡xg(x) = \sin x is continuous on R\mathbb{R}
  • Therefore f(x)=g(h(x))f(x) = g(h(x)) is continuous on R\mathbb{R}

Example 2: f(x)=cos⁡(ln⁡x)f(x) = \cos(\ln x)

Analysis:

  • The inner function h(x)=ln⁡xh(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  • The outer function g(x)=cos⁡xg(x) = \cos x is continuous on R\mathbb{R}
  • Therefore f(x)=g(h(x))f(x) = g(h(x)) is continuous on (0,+∞)(0, +\infty)

Exercises

Exercise 1

Determine the continuity of f(x)=sin⁡(x2)f(x) = \sin(x^2) at x=πx = \pi.

trigonometric functioncontinuityfunction continuity

Approach: Use the continuity of composite functions.

Steps:

  1. The inner function g(x)=x2g(x) = x^2 is continuous on R\mathbb{R}
  2. The outer function h(x)=sin⁡xh(x) = \sin x is continuous on R\mathbb{R}
  3. Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous on R\mathbb{R}
  4. In particular, f(x)f(x) is continuous at x=πx = \pi

Answer: The function is continuous at x=πx = \pi.

Exercise 2

Determine the continuity of f(x)=cos⁡(x3)f(x) = \cos(x^3) at x=0x = 0.

trigonometric functioncontinuityfunction continuity

Approach: Use the continuity of composite functions.

Steps:

  1. The inner function g(x)=x3g(x) = x^3 is continuous on R\mathbb{R}
  2. The outer function h(x)=cos⁡xh(x) = \cos x is continuous on R\mathbb{R}
  3. Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous on R\mathbb{R}
  4. In particular, f(x)f(x) is continuous at x=0x = 0

Answer: The function is continuous at x=0x = 0.

Exercise 3

Determine the continuity of f(x)=tan⁡(x2)f(x) = \tan(x^2) at x=0x = 0.

trigonometric functioncontinuityfunction continuity

Approach: Use the continuity of composite functions.

Steps:

  1. The inner function g(x)=x2g(x) = x^2 is continuous on R\mathbb{R}
  2. The outer function h(x)=tan⁡xh(x) = \tan x is continuous on its domain
  3. Since x2≥0x^2 \geq 0, and tan⁡x\tan x is continuous at x=0x = 0
  4. Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous at x=0x = 0

Answer: The function is continuous at x=0x = 0.

Exercise 4

Determine the continuity of f(x)=sin⁡(1x)f(x) = \sin(\frac{1}{x}) at x=0x = 0.

trigonometric functioncontinuityfunction continuity

Approach: Check whether the function is defined at that point.

Steps:

  1. The function is undefined at x=0x = 0
  2. Therefore the function is discontinuous at x=0x = 0

Answer: The function is discontinuous at x=0x = 0, because the function is undefined at that point.

Exercise 5

Determine the continuity of f(x)=cos⁡(ln⁡x)f(x) = \cos(\ln x) at x=1x = 1.

trigonometric functioncontinuityfunction continuity

Approach: Use the continuity of composite functions.

Steps:

  1. The inner function g(x)=ln⁡xg(x) = \ln x is continuous on (0,+∞)(0, +\infty)
  2. The outer function h(x)=cos⁡xh(x) = \cos x is continuous on R\mathbb{R}
  3. Therefore f(x)=h(g(x))f(x) = h(g(x)) is continuous on (0,+∞)(0, +\infty)
  4. In particular, f(x)f(x) is continuous at x=1x = 1

Answer: The function is continuous at x=1x = 1.

Exercise 6

Let f(x)={sin⁡x,x≤0x+1,x>0f(x) = \begin{cases} \sin x, & x \leq 0 \\ x + 1, & x > 0 \end{cases}. Determine the continuity of f(x)f(x) at x=0x = 0.

trigonometric functioncontinuityfunction continuity

Approach: Compute the left limit, the right limit and the function value separately, and check whether the three are equal.

Steps:

  1. Left limit: lim⁡x→0−f(x)=lim⁡x→0−sin⁡x=0\lim_{x \to 0^-} f(x) = \lim_{x \to 0^-} \sin x = 0
  2. Right limit: lim⁡x→0+f(x)=lim⁡x→0+(x+1)=1\lim_{x \to 0^+} f(x) = \lim_{x \to 0^+} (x + 1) = 1
  3. Function value: f(0)=sin⁡0=0f(0) = \sin 0 = 0
  4. The left limit and the right limit are not equal, so the function is discontinuous at x=0x = 0

Answer: The function is discontinuous at x=0x = 0; this is a jump discontinuity.


Summary

Symbols Used in This Article

SymbolTypePronunciation/ExplanationMeaning in This Article
R\mathbb{R}Mathematical symbolBlackboard bold R (Real numbers)The set of all real numbers
π\piGreek letterPi (pi)The ratio of a circle’s circumference to its diameter, used to denote angles

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