Basic Concepts of Continuity

Continuity means the graph of a function has no breaks. Grasping the concept is essential for learning calculus.

Definition of Continuity

Definition of continuity at a point

Definition of continuity

Let y=f(x)y = f(x) be defined in a neighborhood of x0x_0. If lim⁡x→x0f(x)=f(x0)\lim_{x \to x_0} f(x) = f(x_0), then f(x)f(x) is continuous at x0x_0.

Mathematical description

f(x)f(x) is continuous at x0x_0 if and only if:

  1. f(x0)f(x_0) exists (the function is defined at x0x_0)
  2. lim⁡x→x0f(x)\lim_{x \to x_0} f(x) exists
  3. lim⁡x→x0f(x)=f(x0)\lim_{x \to x_0} f(x) = f(x_0)

Epsilon–delta definition

f(x)f(x) is continuous at x0x_0 iff for any ε>0\varepsilon > 0 there exists δ>0\delta > 0 such that when ∣x−x0∣<δ|x - x_0| < \delta, we have ∣f(x)−f(x0)∣<ε|f(x) - f(x_0)| < \varepsilon.

Geometric Meaning of Continuity

Intuitive view

Geometrically, continuity means the curve has no jumps or breaks at that point.

  • Continuous point: the curve stays connected at the point
  • Discontinuous point: the curve has a jump or gap

Graph features

  1. Continuous functions: the graph is a smooth connected curve
  2. Discontinuous functions: the graph has jumps or gaps at some points

Continuous function example

Discontinuous function example

Basic Properties of Continuity

1. Local Properties

  • Local boundedness: if ff is continuous at x0x_0, it is bounded in a neighborhood of x0x_0
  • Local sign preservation: if ff is continuous at x0x_0 and f(x0)>0f(x_0) > 0, then ff stays positive in some neighborhood of x0x_0

2. Operational Properties

If f(x)f(x) and g(x)g(x) are continuous at x0x_0, then:

  1. Sum/difference: f(x)±g(x)f(x) \pm g(x) is continuous at x0x_0
  2. Product: f(x)⋅g(x)f(x) \cdot g(x) is continuous at x0x_0
  3. Quotient: f(x)g(x)\frac{f(x)}{g(x)} is continuous at x0x_0 if g(x0)≠0g(x_0) \neq 0
  4. Composition: f(g(x))f(g(x)) is continuous at x0x_0 if gg is continuous at x0x_0 and ff is continuous at g(x0)g(x_0)

Exercises

Exercise 1

Determine whether f(x)=x2+1f(x) = x^2 + 1 is continuous at x=2x = 2.

continuityfunction continuity

Approach: Check the definition of continuity.

Steps:

  1. f(2)=22+1=5f(2) = 2^2 + 1 = 5 exists.
  2. lim⁡x→2(x2+1)=5\lim_{x \to 2} (x^2 + 1) = 5.
  3. The limit equals the function value, so it is continuous.

Answer: Continuous.

Exercise 2

Check the continuity of f(x)=1xf(x) = \dfrac{1}{x} at x=0x = 0.

continuityfunction continuity

Approach: Check if the function is defined at the point.

Steps:

  1. f(0)f(0) is undefined.
  2. Therefore the function is not continuous at x=0x = 0.

Answer: Discontinuous because the function is not defined at this point.

Exercise 3

For f(x)={x2,x≤12x−1,x>1f(x) = \begin{cases} x^2, & x \leq 1 \\ 2x - 1, & x > 1 \end{cases}, determine continuity at x=1x = 1.

continuityfunction continuity

Approach: Compare left limit, right limit, and function value.

Steps:

  1. lim⁡x→1−f(x)=1\lim_{x \to 1^-} f(x) = 1
  2. lim⁡x→1+f(x)=1\lim_{x \to 1^+} f(x) = 1
  3. f(1)=1f(1) = 1

Answer: All three are equal, so continuous at x=1x = 1.

Exercise 4

For f(x)={x2,x≤02x+1,x>0f(x) = \begin{cases} x^2, & x \leq 0 \\ 2x + 1, & x > 0 \end{cases}, decide continuity at x=0x = 0.

continuityfunction continuity

Approach: Compute left/right limits and the function value.

Steps:

  1. lim⁡x→0−f(x)=0\lim_{x \to 0^-} f(x) = 0
  2. lim⁡x→0+f(x)=1\lim_{x \to 0^+} f(x) = 1
  3. f(0)=0f(0) = 0

Answer: Left and right limits are unequal, so discontinuous at x=0x = 0.

Exercise 5

Given f(x)f(x) is continuous at x=ax = a and f(a)>0f(a) > 0, prove that there exists δ>0\delta > 0 such that when ∣x−a∣<δ|x - a| < \delta, f(x)>0f(x) > 0.

continuityfunction continuity

Approach: Use the local sign preservation property of continuity.

Steps:

  1. Let ε=f(a)2>0\varepsilon = \dfrac{f(a)}{2} > 0.
  2. By continuity, ∃δ>0\exists \delta > 0 such that ∣x−a∣<δ⇒∣f(x)−f(a)∣<ε|x - a| < \delta \Rightarrow |f(x) - f(a)| < \varepsilon.
  3. Then f(x)>f(a)−ε=f(a)2>0f(x) > f(a) - \varepsilon = \dfrac{f(a)}{2} > 0.

Answer: Such a δ\delta exists that guarantees f(x)>0f(x) > 0.

Exercise 6

Discuss continuity of f(x)=sin⁡xxf(x) = \dfrac{\sin x}{x} at x=0x = 0.

continuityfunction continuity

Approach: Check the function value and limit.

Steps:

  1. f(0)f(0) is undefined, but we can extend by setting f(0)=1f(0) = 1.
  2. lim⁡x→0sin⁡xx=1\lim_{x \to 0} \dfrac{\sin x}{x} = 1.
  3. With f(0)=1f(0)=1, the function becomes continuous at 00; without it, it is not.

Answer: Continuous after extension with f(0)=1f(0)=1, otherwise discontinuous.


Summary

Symbols Used in This Article

SymbolTypePronunciation/ExplanationMeaning in This Article
ε\varepsilonGreek letterEpsilon (epsilon)An arbitrarily small positive number
δ\deltaGreek letterDelta (delta)A positive number paired with ε\varepsilon

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