L'Hôpital's Rule

L’Hôpital’s rule converts certain indeterminate limits into derivative ratios, especially the 00\tfrac{0}{0} and ∞∞\tfrac{\infty}{\infty} types.

Core statement

定理1

Let f,gf,g be defined and differentiable on a punctured neighborhood of aa with g′(x)≠0g'(x)\neq 0. If

  1. lim⁡x→af(x)=lim⁡x→ag(x)=0\lim_{x\to a} f(x) = \lim_{x\to a} g(x) = 0 or ±∞\pm\infty, and
  2. lim⁡x→af′(x)g′(x)\lim_{x\to a} \dfrac{f'(x)}{g'(x)} exists (finite or ±∞\pm\infty),

then

lim⁡x→af(x)g(x)=lim⁡x→af′(x)g′(x).\lim_{x\to a} \frac{f(x)}{g(x)} = \lim_{x\to a} \frac{f'(x)}{g'(x)}.

Indeterminate forms and quick examples

  1. 00\tfrac{0}{0}: lim⁡x→0sin⁡xx=lim⁡cos⁡x1=1\lim_{x\to 0} \dfrac{\sin x}{x} = \lim \dfrac{\cos x}{1} = 1.
  2. ∞∞\tfrac{\infty}{\infty}: lim⁡x→∞x2ex→lim⁡2xex→lim⁡2ex=0\lim_{x\to \infty} \dfrac{x^2}{e^x} \to \lim \dfrac{2x}{e^x} \to \lim \dfrac{2}{e^x} = 0.
  3. 0⋅∞0\cdot\infty: rewrite as quotient, e.g. lim⁡x→0+xln⁡x=lim⁡ln⁡x1/x=0\lim_{x\to 0^+} x\ln x = \lim \dfrac{\ln x}{1/x} = 0.
  4. ∞−∞\infty - \infty: combine terms, then apply the rule.
  5. 000^0, ∞0\infty^0, 1∞1^\infty: take logs to turn into 00\tfrac{0}{0} or ∞∞\tfrac{\infty}{\infty}, e.g. xx=exln⁡xx^x = e^{x\ln x}.

Tips

  • Multiple rounds: check conditions before each application.
  • Pair with Taylor: series often gives the answer faster (e.g., sin⁡x−x\sin x - x).
  • Substitution: change variables to expose an indeterminate form.

Common mistakes

  • Skipping hypothesis checks (continuity/differentiability or g′(x)≠0g'(x)\ne 0).
  • Applying it when the limit is already determinate.
  • Infinite looping: if repeated applications stall, switch methods (Taylor, squeeze, substitution).

Limitations

  • Not for limits that are already determinate.
  • Not usable if derivatives fail to exist or the derivative ratio limit fails.
  • Some problems are better handled by expansions or comparison tests.

Exercises

练习 1

Compute lim⁡x→0sin⁡xx\lim_{x \to 0} \dfrac{\sin x}{x} with L’Hôpital.

Reference Answer(1 个标签)
L'Hospital's rule

00\tfrac{0}{0} type; differentiate numerator/denominator: lim⁡x→0cos⁡x1=1\lim_{x\to 0} \dfrac{\cos x}{1} = 1.

练习 2

Compute lim⁡x→∞x2ex\lim_{x \to \infty} \dfrac{x^2}{e^x}.

Reference Answer(1 个标签)
L'Hospital's rule

∞∞\tfrac{\infty}{\infty} type. First application: lim⁡2xex\lim \dfrac{2x}{e^x}, second: lim⁡2ex=0\lim \dfrac{2}{e^x}=0.

练习 3

Compute lim⁡x→0+xln⁡x\lim_{x \to 0^+} x \ln x.

Reference Answer(1 个标签)
L'Hospital's rule

Rewrite as ln⁡x1/x\dfrac{\ln x}{1/x} (∞∞\tfrac{\infty}{\infty}). Derivatives: 1/x−1/x2=−x→0\dfrac{1/x}{-1/x^2} = -x \to 0.


Summary

本文出现的符号

符号类型读音/说明在本文中的含义
∞\infty数学符号Infinity(无穷大)表示量可以无限增大

中英对照

中文术语英文术语音标说明
洛必达法则L’Hôpital’s rule/loʊpiːˈtɑːlz ruːl/通过导数处理不定式极限
不定式indeterminate form/ɪnˈdɛtərmənət fɔːm/形式无法直接给出极限的表达
零除零zero over zero/ˈzɪərəʊ ˈəʊvə ˈzɪərəʊ/00\frac{0}{0} 型
无穷除无穷infinity over infinity/ɪnˈfɪnəti ˈəʊvə ɪnˈfɪnəti/∞∞\frac{\infty}{\infty} 型
乘积不定式zero times infinity/ˈzɪərəʊ taɪmz ɪnˈfɪnəti/0⋅∞0 \cdot \infty 型
幂指不定式exponential indeterminate/ɪkˌspɒnɛnʃəl ɪnˈdɛtərmənət/00, ∞0, 1∞0^0,\ \infty^0,\ 1^\infty 型
泰勒展开Taylor expansion/ˈteɪlər ɪkˈspænʃən/用多项式逼近函数的方法