General Term Formula of Arithmetic Sequences

The general term formula is the core tool of arithmetic sequences. It allows us to directly find any term of the sequence without computing term by term.

Derivation of the Formula

For an arithmetic sequence {an}\{a_n\}, let the first term be a1a_1 and the common difference be dd. Let us derive the expression for the nnth term ana_n.

According to the definition of an arithmetic sequence:

a2=a1+da3=a2+d=a1+2da4=a3+d=a1+3da5=a4+d=a1+4d\begin{aligned} a_2 &= a_1 + d \\ a_3 &= a_2 + d = a_1 + 2d \\ a_4 &= a_3 + d = a_1 + 3d \\ a_5 &= a_4 + d = a_1 + 4d \\ &\vdots \end{aligned}

Observe the pattern: from a1a_1 to ana_n, we need to add (n1)(n-1) common differences dd.

General term formula of an arithmetic sequence
an=a1+(n1)da_n = a_1 + (n-1)d
Why is it (n-1)d rather than nd?

This is a great question! From a1a_1 to ana_n, we need to go through (n1)(n-1) steps, not nn steps.

Imagine climbing stairs: from the 1st floor to the nnth floor, you need to climb (n1)(n-1) steps. For example, from the 1st floor to the 3rd floor, you only climb 2 steps (1→2, 2→3), not 3.

Similarly, from a1a_1 to ana_n, we need to add the common difference (n1)(n-1) times:

  • a1a_1 to a2a_2: add 1 time
  • a1a_1 to a3a_3: add 2 times
  • a1a_1 to ana_n: add (n1)(n-1) times

Variations of the General Term Formula

The general term formula can also be written in other forms:

Form 1: Based on an Arbitrary Term

If the mmth term ama_m is known, then:

an=am+(nm)da_n = a_m + (n-m)d

This formula is especially useful when a certain term (not necessarily the first) is known.

Form 2: The Linear Function Form

Expanding the general term formula:

an=a1+(n1)d=dn+(a1d)a_n = a_1 + (n-1)d = dn + (a_1 - d)

Let k=dk = d and b=a1db = a_1 - d. Then:

an=kn+ba_n = kn + b

This shows that the general term formula of an arithmetic sequence is a linear function of nn (when d0d \neq 0).

Worked Examples

Example 1: Given the first term and common difference, find a certain term

In the arithmetic sequence {an}\{a_n\}, the first term is a1=3a_1 = 3 and the common difference is d=2d = 2. Find the 10th term a10a_{10}.

Solution:

a10=a1+(101)d=3+9×2=3+18=21a_{10} = a_1 + (10-1)d = 3 + 9 \times 2 = 3 + 18 = 21

Example 2: Given two terms, find the general term formula

In the arithmetic sequence {an}\{a_n\}, a3=7a_3 = 7 and a7=15a_7 = 15. Find the general term formula.

Solution:

Using the general term formula:

{a3=a1+2d=7a7=a1+6d=15\begin{cases} a_3 = a_1 + 2d = 7 \\ a_7 = a_1 + 6d = 15 \end{cases}

Subtracting the two equations: 4d=8d=24d = 8 \quad \Rightarrow \quad d = 2

Substituting into the first equation: a1+2×2=7a1=3a_1 + 2 \times 2 = 7 \quad \Rightarrow \quad a_1 = 3

Therefore, the general term formula is: an=3+(n1)×2=2n+1a_n = 3 + (n-1) \times 2 = 2n + 1

Example 3: Determine whether a number is a term of the sequence

In the arithmetic sequence {an}\{a_n\}, a1=5a_1 = 5 and d=3d = 3. Is 101101 a term of this sequence? If so, which term?

Solution:

Suppose 101101 is the nnth term. Then: an=5+(n1)×3=101a_n = 5 + (n-1) \times 3 = 101 3n+2=1013n + 2 = 101 3n=993n = 99 n=33n = 33

Since n=33n = 33 is a positive integer, 101101 is the 33rd term of this sequence.

Practice Problems

Exercise 1

In the arithmetic sequence {an}\{a_n\}, a1=5a_1 = -5 and d=3d = 3. Find a20a_{20}.

Reference Answer(2 个标签)
arithmetic sequencegeneral term formula

Idea: Use the general term formula an=a1+(n1)da_n = a_1 + (n-1)d directly.

Detailed steps:

a20=a1+(201)d=5+19×3=5+57=52a_{20} = a_1 + (20-1)d = -5 + 19 \times 3 = -5 + 57 = 52

Answer: a20=52a_{20} = 52

Exercise 2

In the arithmetic sequence {an}\{a_n\}, a4=10a_4 = 10 and a9=25a_9 = 25. Find the first term a1a_1 and the common difference dd.

Reference Answer(2 个标签)
arithmetic sequencegeneral term formula

Idea: Set up a system of equations and solve.

Detailed steps:

According to the general term formula:

{a4=a1+3d=10a9=a1+8d=25\begin{cases} a_4 = a_1 + 3d = 10 \\ a_9 = a_1 + 8d = 25 \end{cases}

Subtracting the two equations: 5d=15d=35d = 15 \quad \Rightarrow \quad d = 3

Substituting into the first equation: a1+3×3=10a1=1a_1 + 3 \times 3 = 10 \quad \Rightarrow \quad a_1 = 1

Answer: a1=1a_1 = 1, d=3d = 3

Exercise 3

In the arithmetic sequence {an}\{a_n\}, a1=2a_1 = 2 and d=5d = 5. Is 9797 a term of this sequence?

Reference Answer(2 个标签)
arithmetic sequencegeneral term formula

Idea: Suppose 9797 is the nnth term and check whether nn is a positive integer.

Detailed steps:

Suppose an=97a_n = 97. Then: 2+(n1)×5=972 + (n-1) \times 5 = 97 5n3=975n - 3 = 97 5n=1005n = 100 n=20n = 20

Since n=20n = 20 is a positive integer, 9797 is the 20th term of this sequence.

Answer: Yes, 9797 is the 20th term

Exercise 4

Adapted from a postgraduate entrance examination problem

The arithmetic sequence {an}\{a_n\} satisfies a2+a4=14a_2 + a_4 = 14 and a3+a6=21a_3 + a_6 = 21. Find a1a_1 and dd.

Reference Answer(3 个标签)
arithmetic sequencegeneral term formulasum of first n terms

Idea: Use the general term formula to set up a system of equations.

Detailed steps:

According to the general term formula:

a2+a4=(a1+d)+(a1+3d)=2a1+4d=14a3+a6=(a1+2d)+(a1+5d)=2a1+7d=21\begin{aligned} a_2 + a_4 &= (a_1 + d) + (a_1 + 3d) = 2a_1 + 4d = 14 \\ a_3 + a_6 &= (a_1 + 2d) + (a_1 + 5d) = 2a_1 + 7d = 21 \end{aligned}

Simplifying:

{2a1+4d=14a1+2d=72a1+7d=21\begin{cases} 2a_1 + 4d = 14 \quad \Rightarrow \quad a_1 + 2d = 7 \\ 2a_1 + 7d = 21 \end{cases}

Subtracting the two equations: 3d=7d=733d = 7 \quad \Rightarrow \quad d = \frac{7}{3}

Substituting into the first equation: 2a1+4×73=142a_1 + 4 \times \frac{7}{3} = 14 2a1=14283=42283=1432a_1 = 14 - \frac{28}{3} = \frac{42-28}{3} = \frac{14}{3} a1=73a_1 = \frac{7}{3}

Answer: a1=73a_1 = \frac{7}{3}, d=73d = \frac{7}{3}


Summary

Symbols Used in This Article

符号类型读音/说明在本文中的含义
a1a_1元素符号a sub 1The first term of an arithmetic sequence
ana_n元素符号a sub nThe nnth term of an arithmetic sequence
dd参数differenceThe common difference of an arithmetic sequence
nn变量nThe term number, a positive integer

中英对照

中文术语英文术语音标说明
通项公式general term formula/ˈdʒenərəl tɜːm ˈfɔːmjələ/The formula expressing the nnth term of a sequence
首项first term/fɜːst tɜːm/The first term of a sequence
推导derivation/ˌderɪˈveɪʃən/The process of drawing a conclusion through logical reasoning
线性函数linear function/ˈlɪniə ˈfʌŋkʃən/A function of the form f(x)=kx+bf(x) = kx + b