Loan Repayment

Loan repayment is a typical application of sequences. Understanding the mathematics of repayment plans helps make wise financial decisions.

Two Repayment Methods

1. Equal Principal and Interest

The monthly payment is fixed and includes both principal and interest.

Features:

  • The monthly payment is the same
  • Interest is more in the early period, principal is more in the later period
  • The total interest is higher

2. Equal Principal

The monthly principal payment is fixed, and interest decreases.

Features:

  • The monthly payment decreases
  • Greater payment pressure in the early period
  • The total interest is lower

The Mathematical Model of Equal Principal and Interest

Let the total loan be PP, the monthly interest rate be rr, the number of repayment periods be nn, and the monthly payment be AA.

The outstanding principal PkP_k after the kkth month satisfies the recurrence relation:

Pk+1=Pk(1+r)−AP_{k+1} = P_k(1+r) - A

This is a recurrence relation of the form an+1=qan+da_{n+1} = qa_n + d!

Solving gives:

Monthly payment formula for equal principal and interest
A=P⋅r⋅(1+r)n(1+r)n−1A = \frac{P \cdot r \cdot (1+r)^n}{(1+r)^n - 1}

The Mathematical Model of Equal Principal

Each month the principal repayment is Pn\frac{P}{n}, and the interest in the kkth month is the interest on the outstanding principal.

The payment in the kkth month:

Ak=Pn+[P−(k−1)⋅Pn]⋅r=Pn[1+(n−k+1)r]A_k = \frac{P}{n} + \left[P - (k-1) \cdot \frac{P}{n}\right] \cdot r = \frac{P}{n}[1 + (n-k+1)r]

This is an arithmetic sequence!

Practical Applications

Example 1: Mortgage Calculation

Borrow 1 million yuan at an annual rate of 4.9% for 30 years. Compare the two repayment methods.

Equal principal and interest:

Monthly rate r=4.9%12≈0.00408r = \frac{4.9\%}{12} \approx 0.00408, number of periods n=360n = 360

A=1000000×0.00408×1.004083601.00408360−1≈5307 yuan/monthA = \frac{1000000 \times 0.00408 \times 1.00408^{360}}{1.00408^{360} - 1} \approx 5307 \text{ yuan/month}

Total repayment: 5307×360≈1,910,5205307 \times 360 \approx 1,910,520 yuan Total interest: about 910,000 yuan

Equal principal:

First month payment: 1000000360+1000000×0.00408≈6861\frac{1000000}{360} + 1000000 \times 0.00408 \approx 6861 yuan Last month payment: 1000000360+1000000360×0.00408≈2789\frac{1000000}{360} + \frac{1000000}{360} \times 0.00408 \approx 2789 yuan

Total repayment: about 1,886,000 yuan Total interest: about 890,000 yuan

Early Repayment

If the loan is paid off in a lump sum in the mmth month, how much must be paid?

Equal principal and interest: the outstanding principal is

Pm=P⋅(1+r)n−(1+r)m(1+r)n−1P_m = P \cdot \frac{(1+r)^n - (1+r)^m}{(1+r)^n - 1}

Equal principal: the outstanding principal is

Pm=P−m⋅Pn=P(1−mn)P_m = P - m \cdot \frac{P}{n} = P\left(1 - \frac{m}{n}\right)

Practice Problems

Exercise 1

Borrow 500,000 yuan at an annual rate of 5.4% for 20 years. With the equal-principal-and-interest method, what is the monthly payment?

Reference Answer(2 个标签)
sequence applicationloan repayment

Solution:

Monthly rate r=5.4%12=0.0045r = \frac{5.4\%}{12} = 0.0045, number of periods n=240n = 240

A=500000×0.0045×1.00452401.0045240−1≈3427 yuanA = \frac{500000 \times 0.0045 \times 1.0045^{240}}{1.0045^{240} - 1} \approx 3427 \text{ yuan}

Answer: about 3427 yuan/month


Summary

Symbols Used in This Article

符号类型读音/说明在本文中的含义
PP数学符号capital PTotal loan amount
rr数学符号rMonthly interest rate
nn数学符号nNumber of repayment periods
AA数学符号AMonthly payment
PkP_k数学符号P-sub-kOutstanding principal after the kkth month
AkA_k数学符号A-sub-kPayment in the kkth month
mm数学符号mThe month of early repayment
ana_n数学符号a-sub-nThe nnth term of a recursive sequence
q,dq, d数学符号q, dParameters of the recurrence relation an+1=qan+da_{n+1} = qa_n + d

中英对照

中文术语英文术语音标说明
等额本息equal principal and interest-The monthly payment is fixed
等额本金equal principal-The monthly principal is fixed
月供monthly payment/ˈmʌnθli ˈpeɪmənt/The amount paid each month
剩余本金outstanding principal/aʊtˈstændɪŋ ˈprɪnsəpəl/The principal not yet repaid
递推关系recurrence relation/rɪˈkʌrəns rɪˈleɪʃən/A formula that derives the next term from the previous one