Population Growth

Population growth is a classic application of sequences, from simple exponential growth models to complex Logistic models, all involving sequence knowledge.

The Exponential Growth Model

The simplest population growth model assumes: the population growth rate is fixed each year.

Let the population in year nn be PnP_n and the annual growth rate be rr. Then:

Pn+1=Pn(1+r)P_{n+1} = P_n(1+r)

This is a geometric sequence!

Exponential growth formula
Pn=P0(1+r)nP_n = P_0(1+r)^n

where P0P_0 is the initial population.

Practical Applications

Example 1: City Population Forecast

A city had a population of 1 million in 2020 with an annual growth rate of 2%. Forecast the population in 2030.

Solution:

P10=100×1.0210≈121.9 (ten thousand)P_{10} = 100 \times 1.02^{10} \approx 121.9 \text{ (ten thousand)}

Example 2: Bacterial Reproduction

A certain bacterium divides once every hour (doubling in number). If there are initially 1000 bacteria, how many are there after 6 hours?

Solution:

P6=1000×26=64000 bacteriaP_6 = 1000 \times 2^6 = 64000 \text{ bacteria}

Example 3: Doubling Time

With an annual population growth rate of 3%, how many years until the population doubles?

Solution:

P0×1.03n=2P0P_0 \times 1.03^n = 2P_0 1.03n=21.03^n = 2 n=ln⁡2ln⁡1.03≈23.4 yearsn = \frac{\ln 2}{\ln 1.03} \approx 23.4 \text{ years}

The Logistic Model (Optional)

In reality, populations do not grow without bound; they are limited by resources. The Logistic model takes the environmental carrying capacity KK into account:

Pn+1=Pn+rPn(1−PnK)P_{n+1} = P_n + rP_n\left(1 - \frac{P_n}{K}\right)

As PnP_n approaches KK, the growth rate tends to 0.

Epidemic Transmission Models

The spread of epidemics such as COVID-19 can also be modeled similarly:

In+1=In⋅R0⋅(1−InN)I_{n+1} = I_n \cdot R_0 \cdot \left(1 - \frac{I_n}{N}\right)

where R0R_0 is the basic reproduction number, NN is the total population, and InI_n is the number of infected people on day nn.

Practice Problems

Exercise 1

A country had a population of 50 million in 2020 with an annual growth rate of 1.5%. Forecast the population in 2050.

Reference Answer(2 个标签)
sequence applicationpopulation growth

Solution:

P30=5000×1.01530≈7816 (ten thousand)P_{30} = 5000 \times 1.015^{30} \approx 7816 \text{ (ten thousand)}

Answer: about 78.16 million

Exercise 2

A certain virus spreads at a daily rate of 50% (each infected person infects 0.5 people on average). Initially 10 people are infected. About how many people are infected after 7 days? (Assume the total population is large enough)

Reference Answer(2 个标签)
sequence applicationpopulation growth

Solution:

Simplified model (ignoring environmental carrying capacity):

I7=10×1.57≈171 peopleI_7 = 10 \times 1.5^7 \approx 171 \text{ people}

Answer: about 171 people


Summary

Symbols Used in This Article

符号类型读音/说明在本文中的含义
PnP_n数学符号P-sub-nThe population in year nn
P0P_0数学符号P-sub-zeroThe initial population
rr数学符号rThe annual growth rate
nn数学符号nNumber of years
KK数学符号KThe environmental carrying capacity
R0R_0数学符号R-sub-zeroThe basic reproduction number
NN数学符号NThe total population
InI_n数学符号I-sub-nThe number of infected people on day nn
ln⁡\ln数学符号natural logThe natural logarithm

中英对照

中文术语英文术语音标说明
指数增长exponential growth/ˌekspəˈnenʃəl ɡrəʊθ/Growing at a fixed proportion
增长率growth rate/ɡrəʊθ reɪt/The percentage of growth per period
承载力carrying capacity/ˈkæriɪŋ kəˈpæsəti/The maximum amount the environment can sustain
递推关系recurrence relation/rɪˈkʌrəns rɪˈleɪʃən/A formula that derives the next term from the previous one
基本再生数basic reproduction number/ˈbeɪsɪk ˌriːprəˈdʌkʃən ˈnʌmbə/The average number of people infected by a single infected person