Applications of Important Limits

Important limits are not only the foundation of mathematical theory, but also have wide applications in practice. Mastering these applications can help us better understand the essence of limits.

1. Equivalent Infinitesimals

Using important limits, we can obtain important equivalent infinitesimals, which are very useful in limit computation.

Basic Equivalent Infinitesimals

Basic equivalent infinitesimals

As x→0x \to 0:

  • sin⁡x∼x\sin x \sim x
  • tan⁡x∼x\tan x \sim x
  • ex−1∼xe^x - 1 \sim x
  • ln⁡(1+x)∼x\ln(1 + x) \sim x
  • (1+x)α−1∼αx(1 + x)^\alpha - 1 \sim \alpha x
  • 1−cos⁡x∼x221 - \cos x \sim \frac{x^2}{2}
  • arcsin⁡x∼x\arcsin x \sim x
  • arctan⁡x∼x\arctan x \sim x

These equivalent infinitesimals are very useful in limit computation and can greatly simplify the calculation process.

Applications of Equivalent Infinitesimals

Example 1: Find lim⁡x→0ex−1sin⁡x\lim_{x \to 0} \frac{e^x - 1}{\sin x}

Solution:

  • As x→0x \to 0, ex−1∼xe^x - 1 \sim x and sin⁡x∼x\sin x \sim x
  • Therefore lim⁡x→0ex−1sin⁡x=lim⁡x→0xx=1\lim_{x \to 0} \frac{e^x - 1}{\sin x} = \lim_{x \to 0} \frac{x}{x} = 1

Example 2: Find lim⁡x→0ln⁡(1+x2)x2\lim_{x \to 0} \frac{\ln(1 + x^2)}{x^2}

Solution:

  • As x→0x \to 0, ln⁡(1+x2)∼x2\ln(1 + x^2) \sim x^2
  • Therefore lim⁡x→0ln⁡(1+x2)x2=1\lim_{x \to 0} \frac{\ln(1 + x^2)}{x^2} = 1

2. Limit Computation

Important limits are fundamental tools for computing complicated limits.

Limits of Composite Functions

Example 1: Find lim⁡x→0sin⁡(ex−1)x\lim_{x \to 0} \frac{\sin(e^x - 1)}{x}

Solution:

  1. As x→0x \to 0, ex−1∼xe^x - 1 \sim x
  2. Hence sin⁡(ex−1)∼ex−1∼x\sin(e^x - 1) \sim e^x - 1 \sim x
  3. lim⁡x→0sin⁡(ex−1)x=lim⁡x→0xx=1\lim_{x \to 0} \frac{\sin(e^x - 1)}{x} = \lim_{x \to 0} \frac{x}{x} = 1

Example 2: Find lim⁡x→0esin⁡x−1x\lim_{x \to 0} \frac{e^{\sin x} - 1}{x}

Solution:

  1. As x→0x \to 0, sin⁡x∼x\sin x \sim x
  2. Hence esin⁡x−1∼sin⁡x∼xe^{\sin x} - 1 \sim \sin x \sim x
  3. lim⁡x→0esin⁡x−1x=lim⁡x→0xx=1\lim_{x \to 0} \frac{e^{\sin x} - 1}{x} = \lim_{x \to 0} \frac{x}{x} = 1

Limits of Power-Exponential Functions

Example 1: Find lim⁡x→0(1+x)1x\lim_{x \to 0} (1 + x)^{\frac{1}{x}}

Solution:

  • This is the reciprocal form of the second important limit
  • lim⁡x→0(1+x)1x=e\lim_{x \to 0} (1 + x)^{\frac{1}{x}} = e

Example 2: Find lim⁡x→∞(1+1x2)x2\lim_{x \to \infty} \left(1 + \frac{1}{x^2}\right)^{x^2}

Solution:

  • Let t=x2t = x^2; then as x→∞x \to \infty, t→∞t \to \infty
  • lim⁡x→∞(1+1x2)x2=lim⁡t→∞(1+1t)t=e\lim_{x \to \infty} \left(1 + \frac{1}{x^2}\right)^{x^2} = \lim_{t \to \infty} \left(1 + \frac{1}{t}\right)^t = e

3. Financial Applications

The second important limit has important applications in finance.

Continuously Compounded Interest

In finance, the formula for continuously compounded interest is: A=P⋅ertA = P \cdot e^{rt}

where:

  • AA is the final amount
  • PP is the principal
  • rr is the annual interest rate
  • tt is the time (in years)

Example: If the principal is 1000 yuan, the annual interest rate is 5%, and interest is compounded continuously for 3 years, find the final amount.

Solution: A=1000⋅e0.05×3=1000⋅e0.15≈1161.83A = 1000 \cdot e^{0.05 \times 3} = 1000 \cdot e^{0.15} \approx 1161.83

Present Value

The present value formula is: P=A⋅e−rtP = A \cdot e^{-rt}

Example: If 1000 yuan is needed in 3 years and the annual interest rate is 5%, find the present value.

Solution: P=1000⋅e−0.05×3=1000⋅e−0.15≈860.71P = 1000 \cdot e^{-0.05 \times 3} = 1000 \cdot e^{-0.15} \approx 860.71

4. Physical Applications

Important limits also have applications in physics.

Instantaneous Velocity

The instantaneous velocity is defined as: v=lim⁡Δt→0ΔsΔtv = \lim_{\Delta t \to 0} \frac{\Delta s}{\Delta t}

This is essentially a limiting process.

Instantaneous Acceleration

The instantaneous acceleration is defined as: a=lim⁡Δt→0ΔvΔta = \lim_{\Delta t \to 0} \frac{\Delta v}{\Delta t}

5. Engineering Applications

Signal Processing

In signal processing, the limiting properties of the sine function are used to analyze the frequency characteristics of signals.

Control Systems

In control systems, limits are used to analyze the stability and response characteristics of systems.

Practice Problems

Exercise 1

Find the limit lim⁡x→0ex−1sin⁡x\lim_{x \to 0} \frac{e^x - 1}{\sin x}.

Reference Answer(1 个标签)
applications of important limits

Idea: Use equivalent infinitesimal substitution.

Detailed steps:

  1. As x→0x \to 0, ex−1∼xe^x - 1 \sim x and sin⁡x∼x\sin x \sim x

  2. lim⁡x→0ex−1sin⁡x=lim⁡x→0xx=1\lim_{x \to 0} \frac{e^x - 1}{\sin x} = \lim_{x \to 0} \frac{x}{x} = 1

Answer: The limit is 1.

Exercise 2

Find the limit lim⁡x→0sin⁡(ex−1)x\lim_{x \to 0} \frac{\sin(e^x - 1)}{x}.

Reference Answer(1 个标签)
applications of important limits

Idea: Use the equivalent infinitesimal of a composite function.

Detailed steps:

  1. As x→0x \to 0, ex−1∼xe^x - 1 \sim x

  2. Hence sin⁡(ex−1)∼ex−1∼x\sin(e^x - 1) \sim e^x - 1 \sim x

  3. lim⁡x→0sin⁡(ex−1)x=lim⁡x→0xx=1\lim_{x \to 0} \frac{\sin(e^x - 1)}{x} = \lim_{x \to 0} \frac{x}{x} = 1

Answer: The limit is 1.

Exercise 3

Find the limit lim⁡x→∞(1+2x)x\lim_{x \to \infty} \left(1 + \frac{2}{x}\right)^x.

Reference Answer(1 个标签)
applications of important limits

Idea: Use the generalized form of the second important limit.

Detailed steps:

  1. lim⁡x→∞(1+2x)x=e2\lim_{x \to \infty} \left(1 + \frac{2}{x}\right)^x = e^2

Answer: The limit is e2e^2.

Exercise 4

If the principal is 2000 yuan, the annual interest rate is 6%, and interest is compounded continuously for 5 years, find the final amount.

Reference Answer(1 个标签)
applications of important limits

Idea: Use the continuously compounded interest formula.

Detailed steps:

  1. A=P⋅ert=2000⋅e0.06×5A = P \cdot e^{rt} = 2000 \cdot e^{0.06 \times 5}

  2. =2000⋅e0.3≈2000⋅1.3499≈2699.8= 2000 \cdot e^{0.3} \approx 2000 \cdot 1.3499 \approx 2699.8

Answer: The final amount is approximately 2699.8 yuan.


Summary

Symbols Used in This Article

符号类型读音/说明在本文中的含义
sin⁡\sin数学符号sineA trigonometric function
cos⁡\cos数学符号cosineA trigonometric function
tan⁡\tan数学符号tangentA trigonometric function
arcsin⁡\arcsin数学符号arcsineAn inverse trigonometric function
arctan⁡\arctan数学符号arctangentAn inverse trigonometric function
ee数学符号natural constantThe base of the natural logarithm, approximately 2.71828
ln⁡\ln数学符号natural logarithmThe logarithm with base ee
lim⁡\lim数学符号limitThe limit of a function or sequence
→\to数学符号tends toA variable tending to some value
∼\sim数学符号equivalence signDenotes equivalent infinitesimals
α\alpha希腊字母AlphaOften used as a parameter or exponent

中英对照

中文术语英文术语音标说明
等价无穷小equivalent infinitesimal/ɪˈkwɪvələnt ˌɪnfɪnɪˈtesɪməl/Two infinitesimals whose ratio tends to 1
极限计算limit calculation/ˈlɪmɪt ˌkælkjʊˈleɪʃən/Computing the limit of a function or sequence
连续复利continuous compound interest/kənˈtɪnjuəs ˈkɒmpaʊnd ˈɪntrəst/The limiting case of compound interest
人口增长population growth/ˌpɒpjʊˈleɪʃən ɡroʊθ/The change of population over time
放射性衰变radioactive decay/ˌreɪdiəʊˈæktɪv dɪˈkeɪ/The decrease of radioactive elements over time
变量代换variable substitution/ˈveəriəbəl ˌsʌbstɪˈtjuːʃən/Replacing the original variable with a new one
洛必达法则L’Hôpital’s rule/loʊˈpiːtəlz ruːl/A method for evaluating limits