The Squeeze Theorem

The squeeze theorem is one of the most intuitive and practical criteria for the existence of limits. It determines the limit of a target function by “sandwiching” it between two other functions.

Other Names

The squeeze theorem is also known under different names in various references:

  • Sandwich Theorem (夹值定理)
  • Sandwich Theorem (三明治定理)
  • Squeeze Theorem (挤压定理)
  • Pinching Theorem (夹逼定理)
  • Intermediate Value Theorem for Limits (中间值定理)

All of these names vividly describe the core idea of this criterion: determine the limit of a target function by “sandwiching” it between two functions with known limits.

The Theorem

The squeeze theorem

If in a neighborhood of a point, g(x)≤f(x)≤h(x)g(x) \leq f(x) \leq h(x) always holds, and lim⁡g(x)=lim⁡h(x)=A\lim g(x) = \lim h(x) = A, then

lim⁡f(x)=A\lim f(x) = A.

几何解释

If the function f(x)f(x) is “sandwiched” between two functions g(x)g(x) and h(x)h(x), and the limits of both of these functions tend to the same value AA, then the limit of f(x)f(x) must also be AA.

证明
  1. Since lim⁡g(x)=A\lim g(x) = A, for any ε>0\varepsilon > 0, there exists δ1>0\delta_1 > 0 such that when 0<∣x−x0∣<δ10 < \vert x - x_0 \vert < \delta_1, we have ∣g(x)−A∣<ε\vert g(x) - A \vert < \varepsilon

  2. Since lim⁡h(x)=A\lim h(x) = A, for any ε>0\varepsilon > 0, there exists δ2>0\delta_2 > 0 such that when 0<∣x−x0∣<δ20 < \vert x - x_0 \vert < \delta_2, we have ∣h(x)−A∣<ε\vert h(x) - A \vert < \varepsilon

  3. Let δ=min⁡{δ1,δ2}\delta = \min\{\delta_1, \delta_2\}; then when 0<∣x−x0∣<δ0 < \vert x - x_0 \vert < \delta:

    • A−ε<g(x)≤f(x)≤h(x)<A+εA - \varepsilon < g(x) \leq f(x) \leq h(x) < A + \varepsilon
    • Hence ∣f(x)−A∣<ε\vert f(x) - A \vert < \varepsilon
  4. Therefore lim⁡f(x)=A\lim f(x) = A

符号说明
SymbolTypePronunciation/DescriptionMeaning in this context
ε\varepsilonGreek letterEpsilonAn arbitrarily small positive number
δ\deltaGreek letterDeltaA positive number related to ε\varepsilon

Application Scenarios

  • The function is “sandwiched” between other functions
  • The limit is difficult to compute directly
  • The function has an oscillatory nature
  • It involves the boundedness of trigonometric functions

Practice Problems

Exercise 1

Use the squeeze theorem to find the limit lim⁡x→0x2sin⁡1x\lim_{x \to 0} x^2 \sin \frac{1}{x}.

Reference Answer(1 个标签)
squeeze theorem

Idea: Use the boundedness of the sin⁡\sin function to construct a squeeze inequality.

Detailed steps:

  1. Since −1≤sin⁡1x≤1-1 \leq \sin \frac{1}{x} \leq 1, we have −x2≤x2sin⁡1x≤x2-x^2 \leq x^2 \sin \frac{1}{x} \leq x^2

  2. lim⁡x→0(−x2)=lim⁡x→0x2=0\lim_{x \to 0} (-x^2) = \lim_{x \to 0} x^2 = 0

  3. By the squeeze theorem, lim⁡x→0x2sin⁡1x=0\lim_{x \to 0} x^2 \sin \frac{1}{x} = 0

Answer: The limit is 0.

Exercise 2

Find the limit lim⁡x→0xsin⁡1x\lim_{x \to 0} x \sin \frac{1}{x}.

Reference Answer(1 个标签)
squeeze theorem

Idea: Use the boundedness of the sin⁡\sin function to construct a squeeze inequality.

Detailed steps:

  1. Since −1≤sin⁡1x≤1-1 \leq \sin \frac{1}{x} \leq 1, we have −∣x∣≤xsin⁡1x≤∣x∣-|x| \leq x \sin \frac{1}{x} \leq |x|

  2. lim⁡x→0(−∣x∣)=lim⁡x→0∣x∣=0\lim_{x \to 0} (-|x|) = \lim_{x \to 0} |x| = 0

  3. By the squeeze theorem, lim⁡x→0xsin⁡1x=0\lim_{x \to 0} x \sin \frac{1}{x} = 0

Answer: The limit is 0.

Exercise 3

Find the limit lim⁡x→0x2cos⁡1x\lim_{x \to 0} x^2 \cos \frac{1}{x}.

Reference Answer(1 个标签)
squeeze theorem

Idea: Use the boundedness of the cos⁡\cos function to construct a squeeze inequality.

Detailed steps:

  1. Since −1≤cos⁡1x≤1-1 \leq \cos \frac{1}{x} \leq 1, we have −x2≤x2cos⁡1x≤x2-x^2 \leq x^2 \cos \frac{1}{x} \leq x^2

  2. lim⁡x→0(−x2)=lim⁡x→0x2=0\lim_{x \to 0} (-x^2) = \lim_{x \to 0} x^2 = 0

  3. By the squeeze theorem, lim⁡x→0x2cos⁡1x=0\lim_{x \to 0} x^2 \cos \frac{1}{x} = 0

Answer: The limit is 0.

Exercise 4

Find the limit lim⁡x→∞sin⁡xx\lim_{x \to \infty} \frac{\sin x}{x}.

Reference Answer(1 个标签)
squeeze theorem

Idea: Use the boundedness of the sin⁡\sin function to construct a squeeze inequality.

Detailed steps:

  1. Since −1≤sin⁡x≤1-1 \leq \sin x \leq 1, we have −1x≤sin⁡xx≤1x-\frac{1}{x} \leq \frac{\sin x}{x} \leq \frac{1}{x}

  2. lim⁡x→∞(−1x)=lim⁡x→∞1x=0\lim_{x \to \infty} \left(-\frac{1}{x}\right) = \lim_{x \to \infty} \frac{1}{x} = 0

  3. By the squeeze theorem, lim⁡x→∞sin⁡xx=0\lim_{x \to \infty} \frac{\sin x}{x} = 0

Answer: The limit is 0.


Summary

Symbols Used in This Article

符号类型读音/说明在本文中的含义
lim⁡f(x)\lim f(x)数学符号limit of f of xThe limit of a function
f(x),g(x),h(x)f(x), g(x), h(x)数学符号f/g/h of xTarget, lower bound, and upper bound functions
AA数学符号AThe common limit of the upper and lower bounds
ε\varepsilon希腊字母Epsilon(伊普西隆)An arbitrarily small positive number
δ\delta希腊字母Delta(德尔塔)A positive number related to ε\varepsilon
x0x_0数学符号x-sub-zeroThe limit point
$x$数学符号
sin⁡x,cos⁡x\sin x, \cos x数学符号sine/cosine of xTrigonometric functions
1x\frac{1}{x}数学符号one over xThe reciprocal function
∞\infty数学符号infinityInfinity

中英对照

中文术语英文术语音标说明
夹逼准则squeeze theorem/skwiːz ˈθɪərəm/Finding a limit by squeezing between upper and lower bounds
夹值定理sandwich theorem/ˈsænwɪtʃ ˈθɪərəm/Another name for the squeeze theorem
三明治定理sandwich theorem/ˈsænwɪtʃ ˈθɪərəm/Another name for the squeeze theorem
邻域neighborhood/ˈneɪbəhʊd/The region near the limit point
有界性boundedness/ˈbaʊndɪdnəs/The property that function values stay bounded
振荡oscillate/ˈɒsɪleɪt/To swing back and forth within an interval
极限存在准则criterion for existence of limits/kraɪˈtɪəriən fɔːr ɪɡˈzɪstəns əv ˈlɪmɪts/A method for determining whether a limit exists