Basic Concepts of Limits

Limits are the soul of calculus. They describe how a function behaves near a point and form the bedrock for learning calculus.

Definition of Limits

Function Limits

Definition of a function limit

When xx approaches x0x_0, f(x)f(x) approaches AA, denoted as:

lim⁡x→x0f(x)=A\lim_{x \to x_0} f(x) = A

Mathematical wording: For any ε>0\varepsilon > 0, there exists a δ>0\delta > 0 such that whenever 0<∣x−x0∣<δ0 < \lvert x - x_0 \rvert < \delta, we have ∣f(x)−A∣<ε\lvert f(x) - A \rvert < \varepsilon.

SymbolTypePronunciation/DescriptionMeaning in this context
ε\varepsilonGreek letterEpsilonArbitrarily small positive number
δ\deltaGreek letterDeltaPositive number depending on ε\varepsilon

Sequence Limits

Definition of a sequence limit

When nn approaches infinity, xnx_n approaches AA, denoted as:

lim⁡n→∞xn=A\lim_{n \to \infty} x_n = A

Mathematical wording: For any ε>0\varepsilon > 0, there exists an integer NN such that when n>Nn > N, we have ∣xn−A∣<ε\lvert x_n - A \rvert < \varepsilon.

Examples:

  • lim⁡n→∞1n=0\lim_{n \to \infty} \frac{1}{n} = 0
  • lim⁡n→∞(1+1n)n=e\lim_{n \to \infty} \left(1 + \frac{1}{n}\right)^n = e

Left and Right Limits

Left Limits

Left-hand limit

When xx approaches x0x_0 from the left, the limit of f(x)f(x) is written as:

lim⁡x→x0−f(x)\lim_{x \to x_0^-} f(x)

Mathematical wording: For any ε>0\varepsilon > 0, there exists a δ>0\delta > 0 such that whenever x0−δ<x<x0x_0 - \delta < x < x_0, we have ∣f(x)−A∣<ε\lvert f(x) - A \rvert < \varepsilon.

Right Limits

Right-hand limit

When xx approaches x0x_0 from the right, the limit of f(x)f(x) is written as:

lim⁡x→x0+f(x)\lim_{x \to x_0^+} f(x)

Mathematical wording: For any ε>0\varepsilon > 0, there exists a δ>0\delta > 0 such that whenever x0<x<x0+δx_0 < x < x_0 + \delta, we have ∣f(x)−A∣<ε\lvert f(x) - A \rvert < \varepsilon.

Necessary and Sufficient Condition for Limit Existence

Necessary and Sufficient Condition for Limit Existence

The limit of f(x)f(x) exists at x0x_0 if and only if its left-hand and right-hand limits both exist and are equal.

lim⁡x→x0f(x)=A⇔lim⁡x→x0−f(x)=lim⁡x→x0+f(x)=A\lim_{x \to x_0} f(x) = A \Leftrightarrow \lim_{x \to x_0^-} f(x) = \lim_{x \to x_0^+} f(x) = A

Examples:

  • For f(x)=∣x∣xf(x) = \frac{|x|}{x} at x=0x = 0, the left-hand limit is −1-1 and the right-hand limit is 11, so the limit does not exist.

Properties of Limits

Uniqueness

Uniqueness of Limits

If the limit exists, it is unique.

Proof

Assume lim⁡x→x0f(x)=A\lim_{x \to x_0} f(x) = A and lim⁡x→x0f(x)=B\lim_{x \to x_0} f(x) = B; then A=BA = B.

Boundedness

Boundedness of Limits

If lim⁡x→x0f(x)=A\lim_{x \to x_0} f(x) = A, then there is a neighborhood of x0x_0 on which f(x)f(x) is bounded.

Corollary: If a function has a limit at a point, it must be bounded in some neighborhood of that point.

Sign Preservation

Sign Preservation of Limits

If lim⁡x→x0f(x)=A>0\lim_{x \to x_0} f(x) = A > 0, then there is a neighborhood of x0x_0 where f(x)>0f(x) > 0.

Corollary: If lim⁡x→x0f(x)=A<0\lim_{x \to x_0} f(x) = A < 0, then there is a neighborhood of x0x_0 where f(x)<0f(x) < 0.

Geometric Interpretation of Limits

Geometric Meaning of Function Limits

  • As xx gets arbitrarily close to x0x_0, f(x)f(x) gets arbitrarily close to the constant AA.
  • The graph near x0x_0 clusters around the line y=Ay = A.
  • From either side of x0x_0, f(x)f(x) tends to the same value.

Geometric Meaning of Sequence Limits

  • Points of the sequence on the number line get arbitrarily close to AA.
  • Beyond some term, all points fall inside any neighborhood of AA.
  • The “tail” of the sequence gets closer and closer to its limit.

Exercises

Exercise 1

Determine whether the limit of f(x)=x2−1x−1f(x) = \frac{x^2 - 1}{x - 1} exists at x=1x = 1.

function limitleft-hand limitright-hand limit

Approach: Compute left-hand and right-hand limits and see if they are equal.

Steps:

  1. Right-hand limit: lim⁡x→1+x2−1x−1=lim⁡x→1+(x−1)(x+1)x−1=lim⁡x→1+(x+1)=2\lim_{x \to 1^+} \frac{x^2 - 1}{x - 1} = \lim_{x \to 1^+} \frac{(x-1)(x+1)}{x-1} = \lim_{x \to 1^+} (x+1) = 2
  2. Left-hand limit: lim⁡x→1−x2−1x−1=lim⁡x→1−(x−1)(x+1)x−1=lim⁡x→1−(x+1)=2\lim_{x \to 1^-} \frac{x^2 - 1}{x - 1} = \lim_{x \to 1^-} \frac{(x-1)(x+1)}{x-1} = \lim_{x \to 1^-} (x+1) = 2
  3. Since the left-hand and right-hand limits match, the limit exists.

Answer:The limit exists and equals 22.

Exercise 2

Prove that the sequence xn=nn+1x_n = \frac{n}{n+1} has limit 11.

sequence limit

Approach: Use the definition of a limit: for any ε>0\varepsilon > 0, find NN such that ∣xn−1∣<ε|x_n - 1| < \varepsilon for n>Nn > N.

Steps:

  1. ∣xn−1∣=∣nn+1−1∣=∣n−(n+1)n+1∣=1n+1|x_n - 1| = \left|\frac{n}{n+1} - 1\right| = \left|\frac{n-(n+1)}{n+1}\right| = \frac{1}{n+1}
  2. To make 1n+1<ε\frac{1}{n+1} < \varepsilon, we need n+1>1εn+1 > \frac{1}{\varepsilon}, i.e., n>1ε−1n > \frac{1}{\varepsilon} - 1
  3. Let N=⌊1ε−1⌋+1N = \left\lfloor \frac{1}{\varepsilon} - 1 \right\rfloor + 1; then for n>Nn > N, ∣xn−1∣<ε|x_n - 1| < \varepsilon

Answer:The sequence limit is 11.

Exercise 3

Determine whether the limit of f(x)=1xf(x) = \frac{1}{x} exists at x=0x = 0.

function limitleft-hand limitright-hand limit

Approach: Compute left-hand and right-hand limits.

Steps:

  1. Right-hand limit: lim⁡x→0+1x=+∞\lim_{x \to 0^+} \frac{1}{x} = +\infty
  2. Left-hand limit: lim⁡x→0−1x=−∞\lim_{x \to 0^-} \frac{1}{x} = -\infty
  3. Since they differ, the limit does not exist.

Answer:The limit does not exist.


Summary

Symbols Used in This Article

Symbol notation
SymbolTypePronunciation/ExplanationMeaning in This Article
ε\varepsilonGreek letterEpsilon (/ˈɛpsələn/)Arbitrarily small positive number
δ\deltaGreek letterDelta (/ˈdɛltə/)Positive number depending on ε\varepsilon
NNMathematical symbolPositive integerA sufficiently large positive integer
lim⁡\limMathematical symbolLimitDenotes the limit of a function or sequence
→\toMathematical symbolTends toIndicates approaching a value
∞\inftyMathematical symbolInfinityRepresents infinity
∣x−x0∣\vert x - x_0 \vertMathematical symbolAbsolute valueDistance between xx and x0x_0

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