Lines in Space

The Parametric Equations of a Line

The parametric equations of a line

The parametric equations of the line passing through the point P0(x0,y0,z0)P_0(x_0, y_0, z_0) with direction vector s⃗=(l,m,n)\vec{s} = (l, m, n) are:

{x=x0+lty=y0+mtz=z0+nt\begin{cases} x = x_0 + lt \\ y = y_0 + mt \\ z = z_0 + nt \end{cases}

where tt is the parameter.

The Geometric Meaning of the Parameter

The parameter tt represents the “step size” of moving from the starting point P0P_0 in the direction s⃗\vec{s}:

  • t>0t > 0: moving in the positive direction
  • t<0t < 0: moving in the opposite direction
  • t=0t = 0: at the starting point

The Symmetric Equations of a Line

The symmetric equations of a line

x−x0l=y−y0m=z−z0n\frac{x - x_0}{l} = \frac{y - y_0}{m} = \frac{z - z_0}{n}

where (l,m,n)(l, m, n) is the direction vector and (x0,y0,z0)(x_0, y_0, z_0) is a point on the line.

The Features of the Symmetric Form

  • the form is concise and pleasingly symmetric
  • the direction vector appears directly in the denominators
  • it is suitable for computing the coordinates of points on the line

The Two-Point Form of a Line

The two-point form of a line

The equation of the line passing through the two points P1(x1,y1,z1)P_1(x_1, y_1, z_1) and P2(x2,y2,z2)P_2(x_2, y_2, z_2) is:

x−x1x2−x1=y−y1y2−y1=z−z1z2−z1\frac{x - x_1}{x_2 - x_1} = \frac{y - y_1}{y_2 - y_1} = \frac{z - z_1}{z_2 - z_1}

Applications of the Two-Point Form

  • when two points on the line are known, use the two-point form directly
  • the direction vector is P1P2⃗=(x2−x1,y2−y1,z2−z1)\vec{P_1P_2} = (x_2-x_1, y_2-y_1, z_2-z_1)

The General Form of a Line

The general form of a line
{A1x+B1y+C1z+D1=0A2x+B2y+C2z+D2=0\begin{cases} A_1x + B_1y + C_1z + D_1 = 0 \\ A_2x + B_2y + C_2z + D_2 = 0 \end{cases}

This represents the intersection line of two planes.

The Features of the General Form

  • it is expressed as the intersection of two planes
  • it is suitable for the case where the line intersects planes
  • it does not give the direction vector directly

Converting between the Forms

The Parametric Equations → the Symmetric Equations

From the parametric equations: {x=x0+lty=y0+mtz=z0+nt\begin{cases} x = x_0 + lt \\ y = y_0 + mt \\ z = z_0 + nt \end{cases}

convert to the symmetric form: x−x0l=y−y0m=z−z0n\frac{x - x_0}{l} = \frac{y - y_0}{m} = \frac{z - z_0}{n}

The Symmetric Equations → the Parametric Equations

From the symmetric form: x−x0l=y−y0m=z−z0n=t\frac{x - x_0}{l} = \frac{y - y_0}{m} = \frac{z - z_0}{n} = t

convert to the parametric equations: {x=x0+lty=y0+mtz=z0+nt\begin{cases} x = x_0 + lt \\ y = y_0 + mt \\ z = z_0 + nt \end{cases}


Exercises

Exercise 1

Find the equation of the line passing through the point A(1,2,3)A(1, 2, 3) with direction vector (1,−1,2)(1, -1, 2).

the equation of a lineparametric equationsthe symmetric equations

Approach:

Express the line with the parametric equations and the symmetric equations.

Steps:

  1. The parametric equations: {x=1+ty=2−tz=3+2t\begin{cases} x = 1 + t \\ y = 2 - t \\ z = 3 + 2t \end{cases}

  2. The symmetric equations: x−11=y−2−1=z−32\frac{x - 1}{1} = \frac{y - 2}{-1} = \frac{z - 3}{2}

Answer: The parametric equations: {x=1+ty=2−tz=3+2t\begin{cases} x = 1 + t \\ y = 2 - t \\ z = 3 + 2t \end{cases}

The symmetric equations: x−11=y−2−1=z−32\frac{x - 1}{1} = \frac{y - 2}{-1} = \frac{z - 3}{2}

Exercise 2

Find the equation of the line passing through the two points A(1,2,3)A(1, 2, 3) and B(2,3,4)B(2, 3, 4).

the equation of a linethe two-point formthe direction vector

Approach:

First find the direction vector, and then use the parametric equations or the symmetric equations.

Steps:

  1. The direction vector: AB⃗=(2−1,3−2,4−3)=(1,1,1)\vec{AB} = (2-1, 3-2, 4-3) = (1, 1, 1)

  2. The parametric equations: {x=1+ty=2+tz=3+t\begin{cases} x = 1 + t \\ y = 2 + t \\ z = 3 + t \end{cases}

  3. The symmetric equations: x−11=y−21=z−31\frac{x - 1}{1} = \frac{y - 2}{1} = \frac{z - 3}{1}

Answer: the parametric equations are {x=1+ty=2+tz=3+t\begin{cases} x = 1 + t \\ y = 2 + t \\ z = 3 + t \end{cases}, and the symmetric equations are x−11=y−21=z−31\frac{x - 1}{1} = \frac{y - 2}{1} = \frac{z - 3}{1}


Summary

Symbols Used in This Article

SymbolTypePronunciation/ExplanationMeaning in This Article
s⃗=(l,m,n)\vec{s} = (l, m, n)Direction vectordirection vectorThe direction vector of the line
ttParameterparameterThe parameter in the parametric equations
P0(x0,y0,z0)P_0(x_0, y_0, z_0)Point coordinatespoint coordinatesA point on the line

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