Collinear Vectors

An Intuitive Understanding of Collinearity

Collinear vectors

Two vectors are collinear if, after being freely translated, they lie on the same straight line, with their directions either exactly the same or exactly opposite.

The Necessary and Sufficient Condition for Collinearity

The necessary and sufficient condition for collinearity

Two vectors a⃗,b⃗\vec{a}, \vec{b} are collinear if and only if there exist real numbers k,lk, l, not both zero, such that:

ka⃗+lb⃗=0⃗k\vec{a} + l\vec{b} = \vec{0}
Symbol notation
SymbolTypePronunciation/ExplanationMeaning in This Article
k,lk, lReal numbersReal numbersThe coefficients of the linear combination

How to read the formula:

  • “not both zero” means that kk and ll cannot both be 00
  • if b⃗≠0⃗\vec{b} \neq \vec{0}, this can be rearranged as a⃗=−lkb⃗\vec{a} = -\frac{l}{k}\vec{b} (putting λ=−lk\lambda = -\frac{l}{k})
  • that is, collinear vectors can be written in the scalar-multiple form: a⃗=λb⃗\vec{a} = \lambda\vec{b}

Methods for Testing Collinearity

  1. The scalar-multiple method: check whether there is a real number λ\lambda with a⃗=λb⃗\vec{a} = \lambda\vec{b}
  2. The linear-combination method: check whether there exist k,lk, l not both zero with ka⃗+lb⃗=0⃗k\vec{a} + l\vec{b} = \vec{0}
  3. The coordinate method: compute the ratio between the components of the vectors

Worked Examples and Applications

A positive example: collinear vectors

Example 1: decide whether the vectors a⃗=(3,6)\vec{a} = (3, 6) and b⃗=(1,2)\vec{b} = (1, 2) are collinear.

Solution:

  1. The scalar-multiple relation: a⃗=3b⃗\vec{a} = 3\vec{b}, so a⃗=3b⃗\vec{a} = 3\vec{b}
  2. The linear combination: 1⋅a⃗+(−3)⋅b⃗=3(1,2)+(−3)(1,2)=(3,6)+(−3,−6)=(0,0)1 \cdot \vec{a} + (-3) \cdot \vec{b} = 3(1,2) + (-3)(1,2) = (3,6) + (-3,-6) = (0,0)
  3. The ratio of the coordinates: the xx-component ratio is 3÷1=33\div1=3 and the yy-component ratio is 6÷2=36\div2=3; the ratios are equal

A negative example: non-collinear vectors

Example 2: decide whether the vectors a⃗=(1,2)\vec{a} = (1, 2) and b⃗=(2,3)\vec{b} = (2, 3) are collinear.

Solution:

  1. The ratio of the coordinates: the xx-component ratio is 1÷2=0.51\div2=0.5 and the yy-component ratio is 2÷3≈0.6672\div3\approx0.667; the ratios differ
  2. The linear combination: suppose k(1,2)+l(2,3)=(0,0)k(1,2) + l(2,3) = (0,0)
    • the system: k+2l=0k + 2l = 0, 2k+3l=02k + 3l = 0
    • solving gives k=0k = 0, l=0l = 0 (the only solution is the zero one)

The special case: the zero vector

Example 3: decide whether the zero vector 0⃗\vec{0} and the vector a⃗=(2,5)\vec{a} = (2, 5) are collinear.

Solution:

  • The linear combination: 1⋅0⃗+0⋅a⃗=(0,0)1 \cdot \vec{0} + 0 \cdot \vec{a} = (0,0)
  • The coefficients (1,0)(1, 0) are not both zero

Application Scenarios

Applications in spatial geometry

  1. Equations of lines in space: a line through two points in space can be described by using collinear vectors to represent the position vector of any point on the line
  2. Testing linear combinations: collinearity of vectors is the foundation for studying linear dependence
  3. Geometric transformations: collinear vectors play an important role in transformations such as translation and scaling

A reminder of common misconceptions

Practice

Exercise 1

Decide whether the vectors a⃗=(4,−2)\vec{a} = (4, -2) and b⃗=(−2,1)\vec{b} = (-2, 1) are collinear.

collinear vectorsthe coordinate testlinear combination

Approach:

Use the ratio of the coordinates or the linear-combination method to decide whether the vectors are collinear.

Steps:

  1. Compute the ratio of the coordinates:

    • the xx-component ratio: 4÷(−2)=−24 \div (-2) = -2
    • the yy-component ratio: −2÷1=−2-2 \div 1 = -2
    • the ratios are equal (both are -2)
  2. Or use the linear combination: Suppose k(4,−2)+l(−2,1)=(0,0)k(4,-2) + l(-2,1) = (0,0) The system: 4k−2l=04k - 2l = 0, −2k+l=0-2k + l = 0 Solving gives k=l=0k = l = 0 (the only solution is the zero one)

Answer: The vectors a⃗\vec{a} and b⃗\vec{b} are collinear, and a⃗=−2b⃗\vec{a} = -2\vec{b} (opposite directions).


Summary

Symbols Used in This Article

SymbolTypePronunciation/ExplanationMeaning in This Article
a⃗,b⃗\vec{a}, \vec{b}VectorVector a, bGeneral vectors
0⃗\vec{0}Zero vectorZero vectorThe vector whose components are all zero
k,lk, lReal numbersReal numbersThe coefficients of the linear combination
λ\lambdaReal numberLambdaThe scalar multiplier

Found an issue with this content?

Tell us what could be improved.