This is a beta course, so its structure, chapters, and examples may continue to change.
Sine Series
Definition
定义
定义是对概念、术语或对象含义的精确描述。理解定义是学习任何知识领域的基础,每个概念都有其明确的定义。
The series ∑n=0∞(2n+1)!(−1)nx2n+1 is called the sine series.
符号说明
| Symbol | Type | Pronunciation/Explanation | Meaning in This Article |
|---|
| ∑ | Greek letter | Sigma | Summation symbol, representing series |
| ∞ | Mathematical symbol | Infinity | Represents infinite series, infinite number of terms |
| n! | Mathematical symbol | Factorial | n factorial, n!=n×(n−1)×⋯×1 |
Convergence
数学定理
定理是数学中经过严格证明的命题,是数学推理的基础。定理通常包含条件和结论,是数学知识体系的重要组成部分。
Sine Series Convergence
For any real number x, the series converges, and its sum is:
∑n=0∞(2n+1)!(−1)nx2n+1=sinx
证明
Using the ratio test:
anan+1=(2(n+1)+1)!(−1)n+1x2(n+1)+1⋅(−1)nx2n+1(2n+1)!=−(2n+2)(2n+3)x2
limn→∞anan+1=limn→∞(2n+2)(2n+3)x2=0<1
Therefore, for any real number x, the series converges.
Examples
Example 1
Find the sum of the series ∑n=0∞(2n+1)!(−1)n(2π)2n+1.
Solution:
This is the sine series with x=2π.
Therefore, the sum is: sin(2π)=1
Example 2
Find the sum of the series ∑n=0∞(2n+1)!(−1)nπ2n+1.
Solution:
This is the sine series with x=π.
Therefore, the sum is: sin(π)=0
Exercises
Exercise 1
Find the sum of the series ∑n=0∞(2n+1)!(−1)n(6π)2n+1.
Reference Answer(2 个标签)
sine seriesseries summation
Solution Approach:
This is the sine series, need to determine the value of x.
Detailed Steps:
- Identify series type: ∑n=0∞(2n+1)!(−1)n(6π)2n+1 is the sine series
- Determine parameter: x=6π
- Calculate sum: S=sin(6π)=21
Answer:
The sum is 21.
Exercise 2
Find the sum of the series ∑n=0∞(2n+1)!(−1)n(3π)2n+1.
Reference Answer(2 个标签)
sine seriesseries summation
Solution Approach:
This is the sine series, need to determine the value of x.
Detailed Steps:
- Identify series type: ∑n=0∞(2n+1)!(−1)n(3π)2n+1 is the sine series
- Determine parameter: x=3π
- Calculate sum: S=sin(3π)=23
Answer:
The sum is 23.
Exercise 3
Find the sum of the series ∑n=0∞(2n+1)!(−1)n(4π)2n+1.
Reference Answer(2 个标签)
sine seriesseries summation
Solution Approach:
This is the sine series, need to determine the value of x.
Detailed Steps:
- Identify series type: ∑n=0∞(2n+1)!(−1)n(4π)2n+1 is the sine series
- Determine parameter: x=4π
- Calculate sum: S=sin(4π)=22
Answer:
The sum is 22.
Summary
Symbols Appearing in This Article
| Symbol | Type | Pronunciation/Explanation | Meaning in This Article |
|---|
| x | Mathematical symbol | Variable | Variable in the sine series |
| π | Greek letter | Pi | Pi, approximately 3.14159 |
| sin | Mathematical symbol | Sine | Sine function |
| lim | Mathematical symbol | Limit | Represents the limit of a sequence or function |
Chinese-English Glossary
| Chinese Term | English Term | Phonetic | Explanation |
|---|
| Sine series | sine series | /saɪn ˈsɪəriːz/ | Series of the form ∑n=0∞(2n+1)!(−1)nx2n+1 |
| Convergence | convergence | /kənˈvɜːdʒəns/ | Series partial sums have a finite limit |
| Ratio test | ratio test | /ˈreɪʃiəʊ test/ | Method to determine convergence using ratio of adjacent terms |