导航菜单

Geometric Series

Definition of Geometric Series

Definition of Geometric Series

The series n=0arn\sum_{n=0}^{\infty} ar^n is called a geometric series, where a0a \neq 0.

符号说明
SymbolTypePronunciation/ExplanationMeaning in This Article
\sumGreek letterSigmaSummation symbol, representing series
\inftyMathematical symbolInfinityRepresents infinite series, infinite number of terms
rrMathematical symbolCommon ratioRatio between consecutive terms in geometric series

Convergence

Geometric Series Convergence

When r<1|r| < 1, the series converges, and its sum is:

n=0arn=a1r\sum_{n=0}^{\infty} ar^n = \frac{a}{1 - r}

When r1|r| \geq 1, the series diverges.

证明
  1. Let Sn=a+ar+ar2++arn1S_n = a + ar + ar^2 + \cdots + ar^{n-1}, then multiply by rr to get: rSn=ar+ar2++arnrS_n = ar + ar^2 + \cdots + ar^n
  2. Subtract the two equations: (1r)Sn=aarn=a(1rn)(1 - r)S_n = a - ar^n = a(1 - r^n)
  3. If r<1|r| < 1, then limnrn=0\lim_{n \to \infty} r^n = 0, so: limnSn=a1r\lim_{n \to \infty} S_n = \frac{a}{1 - r}
  4. When r1|r| \geq 1, the partial sums do not converge, hence the series diverges.

Examples

Example 1

Determine the convergence of the series n=012n\sum_{n=0}^{\infty} \frac{1}{2^n} and find its sum if it converges.

Solution: This is a geometric series with a=1,r=12a = 1, r = \frac{1}{2}

Since r=12<1|r| = \frac{1}{2} < 1, the series converges.

The sum is: S=a1r=1112=2S = \frac{a}{1 - r} = \frac{1}{1 - \frac{1}{2}} = 2

Example 2

Determine the convergence of the series n=013n\sum_{n=0}^{\infty} \frac{1}{3^n} and find its sum if it converges.

Solution: This is a geometric series with a=1,r=13a = 1, r = \frac{1}{3}

Since r=13<1|r| = \frac{1}{3} < 1, the series converges.

The sum is: S=a1r=1113=32S = \frac{a}{1 - r} = \frac{1}{1 - \frac{1}{3}} = \frac{3}{2}

Example 3

Determine the convergence of the series n=02n\sum_{n=0}^{\infty} 2^n.

Solution: This is a geometric series with a=1,r=2a = 1, r = 2

Since r=21|r| = 2 \geq 1, the series diverges.

Exercises

Exercise 1

Determine the convergence of the series n=014n\sum_{n=0}^{\infty} \frac{1}{4^n} and find its sum if it converges.

Reference Answer (3 个标签)
geometric series series convergence series summation

Problem-solving approach: This is a geometric series; we need to determine the relationship between the absolute value of the common ratio and 1.

Detailed steps:

  1. Identify the series type: n=014n\sum_{n=0}^{\infty} \frac{1}{4^n} is a geometric series
  2. Determine parameters: a=1,r=14a = 1, r = \frac{1}{4}
  3. Check convergence: r=14<1|r| = \frac{1}{4} < 1, so the series converges
  4. Calculate the sum: S=a1r=1114=43S = \frac{a}{1-r} = \frac{1}{1-\frac{1}{4}} = \frac{4}{3}

Answer: The series converges with sum 43\frac{4}{3}.

Exercise 2

Determine the convergence of the series n=025n\sum_{n=0}^{\infty} \frac{2}{5^n} and find its sum if it converges.

Reference Answer (3 个标签)
geometric series series convergence series summation

Problem-solving approach: This is a geometric series; we need to determine the relationship between the absolute value of the common ratio and 1.

Detailed steps:

  1. Identify the series type: n=025n\sum_{n=0}^{\infty} \frac{2}{5^n} is a geometric series
  2. Determine parameters: a=2,r=15a = 2, r = \frac{1}{5}
  3. Check convergence: r=15<1|r| = \frac{1}{5} < 1, so the series converges
  4. Calculate the sum: S=a1r=2115=245=52S = \frac{a}{1-r} = \frac{2}{1-\frac{1}{5}} = \frac{2}{\frac{4}{5}} = \frac{5}{2}

Answer: The series converges with sum 52\frac{5}{2}.

Exercise 3

Determine the convergence of the series n=0(1)n\sum_{n=0}^{\infty} (-1)^n.

Reference Answer (2 个标签)
geometric series series convergence

Problem-solving approach: This is a geometric series; we need to determine the relationship between the absolute value of the common ratio and 1.

Detailed steps:

  1. Identify the series type: n=0(1)n\sum_{n=0}^{\infty} (-1)^n is a geometric series
  2. Determine parameters: a=1,r=1a = 1, r = -1
  3. Check convergence: r=1=11|r| = |-1| = 1 \geq 1, so the series diverges

Answer: The series diverges.


Summary

Symbols Used in This Article

SymbolTypePronunciation/ExplanationMeaning in This Article
aaMathematical symbolFirst termFirst term of geometric series
SnS_nMathematical symbolPartial sumSum of first nn terms of the series
lim\limMathematical symbolLimitRepresents limit of sequence or function

Chinese-English Glossary

Chinese TermEnglish TermIPA PronunciationExplanation
几何级数geometric series/dʒiːəˈmetrɪk ˈsɪəriːz/Series of the form n=0arn\sum_{n=0}^{\infty} ar^n
公比common ratio/ˈkɒmən ˈreɪʃiəʊ/Ratio between consecutive terms rr in geometric series
首项first term/fɜːst tɜːm/First term aa of geometric series
收敛convergence/kənˈvɜːdʒəns/Partial sums sequence has a finite limit
发散divergence/daɪˈvɜːdʒəns/Partial sums sequence has no finite limit
sum/sʌm/Limit value of convergent series
部分和partial sum/ˈpɑːʃəl sʌm/Sum of first nn terms SnS_n of the series

课程路线图

  1. 1

    Exploring Functions in Advanced Mathematics

    先修课程

    Functions are a core idea of advanced mathematics. This course walks through foundational concepts, key properties, and classic constants so you can read, reason, and compute with confidence.

    前往课程
  2. 2

    Sequences

    先修课程

    Sequences bridge discrete thinking and calculus. This track covers core definitions, limits, convergence, and classic models.

    前往课程
  3. 3

    The World of Limits in Advanced Mathematics

    先修课程

    Limits are the foundation of calculus and one of the most important ideas in advanced mathematics.

    前往课程
  4. 4

    Infinite Series

    当前课程

    Explore convergence tests, summation, power-series expansions, and applications.

    前往课程

搜索